1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hammer [34]
3 years ago
7

You are on roller blades on top of a small hill. Your potential energy is equal to 1,000.0 joules. The last time

Physics
1 answer:
irinina [24]3 years ago
8 0
It is -59 i think or just ask someone esle for help
You might be interested in
A 15x10^-6c charge is placed at the origin and a 9x10^-6C charge is placed on the x-axis at x=1.00m. where, on the x-axis is the
Harlamova29_29 [7]

The Electric field is zero at a distance 2.492 cm from the origin.

Let A be point where the charge 15\times10^-6 C is placed which is the origin.

Let B be the point where the charge 9\times 10^-6 C is placed. Given that B is at a distance 1 cm from the origin.

Both the charges are positive. But charge at origin is greater than that of B. So we can conclude that the point on the x-axis where the electric field = 0 is after B on x - axis.

i.e., at distance 'x' from B.

Using Coulomb's law, \frac{kQ_A^2}{d_A^2} = \frac{kQ_B^2}{d_B^2},

Q_A = 15\times 10^-6 C

Q_B=9\times10^-6C

d_A = 1+x cm

d_B=x cm

k is the Coulomb's law constant.

On substituting the values into the above equation, we get,

\frac{(15\times10^-6)^2}{(1+x)^2} =\frac{(9\times10^-6)^2}{x^2}

Taking square roots on both sides and simplifying and solving for x, we get,

1.67x = 1+x

Therefore, x = 1.492 cm

Hence the electric field is zero at a distance 1+1.492 = 2.492 cm from the origin.

Learn more about Electric fields and Coulomb's Law at brainly.com/question/506926

#SPJ4

3 0
1 year ago
A 18.0-kg rock is sliding on a rough, horizontal surface at 7.10 m/s and eventually stops due to friction. the coefficient of ki
Bond [772]
A = .3*g = 2.94 m/s² 

<span>t = v/a = 9/2.94 = 3.061 sec </span>

<span>W = E/t = ½mv²/t = ½*40*9²/3.061 = 529.2 watts</span>
4 0
3 years ago
1. Two forces F~ 1 and F~ 2 are acting on a block of mass m=1.5 kg. The magnitude of force F~ 1 is 12N and it makes an angle of
VLD [36.1K]

Answer:

Normal force=7.48 N

Explanation:

N+F~1 sinθ-mg=0

=>N=1.5*9.8-12 sin37◦

=>N=14.7-7.22=7.48 N

6 0
3 years ago
How does a 12-month lunar calendar differ from our 12-month solar calendar?.
horrorfan [7]

Answer:

It has about 11 fewer days. It does not have seasons. Its new year always occurs in February instead of on January 1.

Explanation:

8 0
2 years ago
a box with a weight of 555 N is sitting on the ground and the bottom of the box measures 0.55 m by 0.45. What is the pressure ex
IrinaK [193]

Explanation:

Pressure = force / area

P = 55 N / (0.55 m × 0.45 m)

P = 220 Pa

8 0
3 years ago
Other questions:
  • What if the earth was flat
    14·2 answers
  • Which was the first object made by humans to orbit earth?
    14·1 answer
  • A rock is dropped from a tower 70.0 m high. How long does it take for the rock to hit the ground? *
    15·1 answer
  • How does a body move if it's constantly under force?
    9·2 answers
  • A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou
    15·1 answer
  • Hi
    7·1 answer
  • Which variables are involved in understanding Kepler's third law of motion? (1 point)
    13·2 answers
  • Please solve the Problem.
    14·1 answer
  • How an electric car might still run on fossil fuel
    14·1 answer
  • The cosmic microwave background essentially looks the same in all directions. This is an example of.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!