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Gemiola [76]
3 years ago
10

When dots are further apart on a ticker-tape diagram, it indicates an object is moving

Physics
2 answers:
Aloiza [94]3 years ago
5 0

Answer:

At a higher velocity.

Musya8 [376]3 years ago
4 0
At a higher velocity.

Hope this helps!
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A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y
blsea [12.9K]

Answer:

Negative z-direction

Explanation:

First of all, we need to understand the direction of the magnetic force on the proton. This can be determined by using the right hand rule. So we have:

- index finger: direction of the proton, positive x-direction

- middle finger: direction of magnetic field, positive y-direction

- thumb: direction of the force, positive z-direction

In order to balance this magnetic force, the electric force must act in the opposite direction (negative z direction). Since for a proton (positive charge) the force and the electric field have same direction, it means that the electric field must also be in the negative z direction.

3 0
3 years ago
Travel north to south how would polaris be situated?
valentina_108 [34]

Answer:

idi

Explanation:

3 0
4 years ago
How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?​
Anon25 [30]

Answer:

5.98 m

Explanation:

T=2\pi \sqrt\frac{L}{g}

T^2=4\pi ^2L/g\\L = gT^2/(4\pi^2) = 11.15*4.6²/(4π²) = 5.98 m

5 0
2 years ago
The particle starts from rest at t=0. What is the magnitude p of the momentum of the particle at time t? Assume that t>0. Exp
olganol [36]

Answer:

Ft

Explanation:

We are given that

Initial velocity=u=0

We have to find the magnitude of p of the momentum of the particle at time t.

Let mass of particle=m

Applied force=F

Acceleration, a=\frac{F}{m}

Final velocity , v=a+ut

Substitute the values

v=0+\frac{F}{m}t=\frac{F}{m}t

We know that

Momentum, p=mv

Using the formula

p=m\times \frac{F}{m}t=Ft

6 0
4 years ago
A racecar traveling at a velocity of 18.5 m/s, accelerates at a rate of 2.47 m/s2 and covers a distance of 79.78 m. Determine th
Vesna [10]

Answer:

The final velocity of the race car is 27.14 m/s

Explanation:

Given;

initial velocity of the race car, u = 18.5 m/s

acceleration of the race car, a = 2.47 m/s²

distance covered by the race car, s = 79.78 m

Apply the following kinematic equation to determine the final velocity of the race car.

v² = u² + 2as

v² = (18.5)² + 2(2.47)(79.78)

v² = 736.363

v = √736.363

v = 27.14 m/s

Therefore, the final velocity of the racecar is 27.14 m/s

4 0
4 years ago
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