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tigry1 [53]
3 years ago
14

How many solutions does the system of equations below have? Y=2x - 6 y=5/9x+9/4

Mathematics
2 answers:
kramer3 years ago
6 0

Answer:

2

Step-by-step explanation:

next two the = there are 2 ys

satela [25.4K]3 years ago
4 0

Answer:

Only 1

Step-by-step explanation:

It does not have the same slope thus meaning its not it does not have infinite or no solution, which leaves out 1 solution

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B

12000 divides by 2880 is 42! Hope this could help

Step-by-step explanation:

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When x=8 y=20. What is y when x=42?
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If you would like to know what is y when x = 42, you can calculate this using the following steps:

x = 8 ... y = 20
x = 42 ... y = ? 

8 * y = 20 * 42      /8
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The correct result would be: y = 105 when x = 42.
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When you're writing an essay to evaluate something as "good" or "bad" what is MOST important to include in your
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2 years ago
The Magazine Mass Marketing Company has received 1515 entries in its latest sweepstakes. They know that the probability of recei
wariber [46]

Answer:

P(x < 5)=P(X=0)+P(X=1)+P(X=2)+P(x=3)+P(X=4)

P(X=0)=(15C0)(0.5)^0 (1-0.5)^{15-0}=0.0000305

P(X=1)=(15C1)(0.5)^1 (1-0.5)^{15-1}=0.000458

P(X=2)=(15C2)(0.5)^2 (1-0.5)^{15-2}=0.0032

P(X=3)=(15C3)(0.5)^3 (1-0.5)^{15-3}=0.0139

P(X=4)=(15C4)(0.5)^4 (1-0.5)^{15-4}=0.0417

And adding we got:

P(x < 5)=0.0592

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=15, p=0.5)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(x < 5)=P(X=0)+P(X=1)+P(X=2)+P(x=3)+P(X=4)

P(X=0)=(15C0)(0.5)^0 (1-0.5)^{15-0}=0.0000305

P(X=1)=(15C1)(0.5)^1 (1-0.5)^{15-1}=0.000458

P(X=2)=(15C2)(0.5)^2 (1-0.5)^{15-2}=0.0032

P(X=3)=(15C3)(0.5)^3 (1-0.5)^{15-3}=0.0139

P(X=4)=(15C4)(0.5)^4 (1-0.5)^{15-4}=0.0417

And adding we got:

P(x < 5)=0.0592

7 0
3 years ago
I need to make this expression true by using grouping symbols. 2x2+3^2 -4+3x5
Novay_Z [31]
Simply 3^2 to 9

2×2+9−4+3×5

Simplify 2 x 2 to 4

4+9−4+3×5

Simplify 3 x 5 to 15

4+9−4+15

Simplify

= 24
7 0
4 years ago
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