Solve the equation by completing the square 5x(x+6)=-50

1 answer:

3 0

First lets distribute the 5x
5x^2 + 30x = -50

Lets divide every term by 5
x^2 + 6x = -10

To complete the square we have to half the b value, which in this case is 6. Then square it.
Half of 6 is 3, 3 squared is 9

Add that to both sides of the equation
x^2 + 6x + 9 = -1

Find the binomial squared
(x+3)^2 (If you're wondering how i got that please comment)

(x+3)^2 = -1

Take the square root of the equation of both sides
(x+3) = +/- i
x = -3 +/- i
x = -3 - i
and
x = -3 + i

You might be interested in

Nichol walks at a constant pace of 1.2 m/s and takes 15 minutes to get to school.

liraira [26]

Answer:

The difference between the distances they walked is 600 meters.

Step-by-step explanation:

Let's calculate the distance traveled by Nichol and Sakura with the following equation:

$d = v*t$

Where:

v: is the speed

t: is the time

The distance traveled by Nichol is:

$d_{n} = 1.2 m/s*15min*\frac{60 s}{1 min} = 1080 m$

And the distance traveled by Sakura is:

$d_{s} = 1.4 m/s*20 min*\frac{60 s}{1 min} = 1680 m$

Hence, the difference between the distances they walked is:

$d_{t} = d_{s} - d_{n} = 1680 m - 1080 m = 600 m$

Sakura traveled 600 meters more than Nichol.

Therefore, the difference between the distances they walked is 600 meters.

I hope it helps you!

4 0

2 years ago

A cell phone provider offers a plan that costs $40 per month plus $0.20 per text message sent or received. A comparable plan c

Svetradugi [14.3K]

You do the following.

Take the price of the most expensive subscription and retract the price of the cheap one.

$50-$40 = $10

Since we know what the price of a text message and the difference in dollars between the two subscriptions, we can calculate how many text messages has to be sent. We just divide the result from before ($10) with the price of a text message ($0.2)

$10/$0.2 = 50

The total number of text messages that needs to be send in order for the price of the subscriptions to be the same, is 50.

4 0

3 years ago

Please help. Write as a single logarithm, a) log(13)+log(4) b) log(small 5)(14)-log(small 5)(2)

dsp73

Answer:

a) $\log 52$