Answer:
hshshxhdjebrbhdjwjdbevvdhdhfiiehrvrvdhdjrirubrvfgdhjdjejrhvrvdghfueyrggdvdvdgdhdudhdhegdghdhhrhdbdbdbhdhdhfhfydhhdbfbdbdbrbrhhrhrhrhfhfuyfh4h4bbdbdhxufhfbbdhdhdhrhffbfbdbduc
We have to factor becasue
area=legnth times width
area=4x^2+28x+49
area=(2x+7)(2x+7)
area=(2x+7)^2
legnth =width
we arent' given area so we can't solve
but, , since it is a squaer room, legnth=width so √area=legnth=width
100%/x%=20/15
(100/X)*x=20/15*x --I multiply both sides of the equation by X
100=1.33333333333*x --I divided both sides of the equation by .........................................(1.33333333333) to get X
100/1.33333333333=x
75=x
x=75
15 is 75% of 20
Answer:
- <u>The complement of spinning any number less than 3, is spinning a number equal to or greater than 3.</u>
Explanation:
The complement of a subset is the subset of elements that are not in the given subset.
You must know which numbers the spinner has.
Assuming the spinner has the numbers 1, 2, 3, 4, the complement of spinning any number less than 3, is spinning a number that is not less than 3.
Then, that is spinning a number that is equal to or greater than 3.
The numbers that are equal to or greater than four, for a spinner that has the numbers 1, 2, 3, and 4 are 3 and 4.
Thus, the complement of spinning any number less than 3 is spinning a three or a four.
Step-by-step explanation:
f(2)= -2×2×2+ 6×2 -7
=-8+12-7
=-3
