According to Newton;s Second Law of motion, F = ma. Acceleration is the change of velocity per unit time. Since there is no change of velocity, then acceleration is equal to zero. Consequently, the net force F is also equal to zero. The net force is equal to the sum of all the forces acting on the body. These forces are the horizontal force and the frictional force. They are acting in opposite directions. So, the sum must be
F = 0 = Horizontal - Frictional
0 = 100 N - Frictional
Frictional force = 100 N
Explanation:
The period is the time it takes for the spinner to rotate one revolution, or 2π radians.
T = 2π / ω
T = (2π rad) / (140 rad/s)
T = 0.0449 s
The tangential velocity is the product of the angular velocity and the radius.
v = ωr
v = (140 rad/s) (3.7 cm)
v = 518 cm/s
Answer:
The velocity of the wave is, v = 180,000 m/s
Explanation:
Given data,
The frequency of the wave, f = 900 Hz
The wavelength of the wave, λ = 200 m
The formula for the speed of the wave when the frequency and wavelength are known,
v = λ x f
Substituting the given values in the above equation,
v = 200 m x 900 Hz
v = 180000 m/s
Hence, the velocity of the wave is, v = 180,000 m/s
Daniel applies a 30 Newtons force on the ball that sends the ball 300 meters, which gives the work done by Daniel as 9 kJ
<h3>How can the work done be obtained from the given force and distance?</h3>
The given parameters are;
The force with which Daniel hit the ball = 30 Newtons
The distance the ball flew, following the application of the force = 300 meters
Required;
The amount of work done on the ball by Daniel
Solution:
- Work done = Force applied × Distance moved in the direction of the force
Therefore;
The work done by Daniel on the ball, <em>W</em>, can be calculated as follows;
W = 30 N × 300 m = 9000 J = 9 kJ
- The work done by Daniel on the ball is 9 kJ
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