All categories

3 years ago

If a net horizontal force of 175 N is applied to a bike whose mass is 50 kg what acceleration is produced?

Physics

1 answer:

Crazy boy [7]3 years ago

7 0

The acceleration of the bike is $3.5 m/s^2$

Explanation:

We can solve this problem by using Newton's second law of motion, which states that:

$F=ma$

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the bike in this problem, we have

F = 175 N is the net force

m = 50 kg is the mass

And solving for a, we find the acceleration:

$a=\frac{F}{m}=\frac{175}{50}=3.5 m/s^2$

Learn more about Newton's second law and acceleration:

brainly.com/question/3820012

#LearnwithBrainly

You might be interested in

A 1.00 kg particle has the xy coordinates (-1.20 m, 0.500 m) and a 4.50 kg particle has the xy coordinates (0.600 m, -0.750 m).

just olya [345]

Answer:

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

Explanation:

The center of mass of a system of particles ( $\vec r_{cm}$ ), measured in meters, is defined by this weighted average:

$\vec r_{cm} = \frac{\Sigma_{i=1}^{n}\,m_{i}\cdot \vec r_{i}}{\Sigma_{i=1}^{n}\,m_{i}}$ (1)

Where:

$m_{i}$ - Mass of the i-th particle, measured in kilograms.

$\vec r_{i}$ - Location of the i-th particle with respect to origin, measured in meters.

If we know that $\vec r_{cm} = (-0.500\,m,-0.700\,m)$ , $m_{1} = 1\,kg$ , $\vec r_{1} = (-1.20\,m, 0.500\,m)$ , $m_{2} = 4.50\,kg$ , $\vec r_{2} = (0.600\,m, -0.750\,m)$ and $m_{3} = 4\,kg$ , then the coordinates of the third particle are:

$(-0.500\,m, -0.700\,m) = \frac{(1\,kg)\cdot (-1.20\,m,0.500\,m)+(4.50\,kg)\cdot (0.600\,m,-0.750\,m)+(4\,kg)\cdot \vec r_{3}}{1\,kg+4.50\,kg+4\,kg}$

$(-4.75\,kg\cdot m, -6.65\,kg\cdot m) = (-1.20\,kg\cdot m, 0.500\,kg\cdot m) + (2.7\,kg\cdot m, -3.375\,kg\cdot m) +(4\cdot x_{3},4\cdot y_{3})$

$(4\cdot x_{3}, 4\cdot y_{3}) = (-6.25\,kg\cdot m,-3.775\,kg\cdot m)$

$(x_{3},y_{3}) = (-1.562\,m,-0.944\,m)$

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

5 0

3 years ago

Who else got stuck on a question and is NOT ready for test return at 2? its 1:58 AAAAAAA

k0ka [10]

Good luckkkk hope you do well

3 0

2 years ago

two soccer players run toward each other. one player has a mass of 85 kg and runs west with a speed of 8 m/s, while the other ha

marissa [1.9K]

Answer:

Total momentum, p = 55 kg-m/s

Explanation:

It is given that,

Mass of player 1, m₁ = 85 kg

Mass of player 2, m₂ = 105 kg

Speed of player 1, v₁ = -8 m/s (west)

Speed of player 2, v₂ = 7 m/s (east)

Momentum is equal to the product of mass and velocity. For this system, momentum is given by :

$p=m_1v_1+m_2v_2$

$p=85\ kg\times (-8\ m/s)+105\ kg\times 7\ m/s$

p = 55 kg-m/s

The total momentum of the system made up of the two players is 55 kg-m/s.

8 0

3 years ago

Read 2 more answers

Longitudinal wave is mechanical wave why

Katarina [22]

Explanation:

Mechanical Waves are waves which propagate through a material medium (solid, liquid, or gas) at a wave speed which depends on the elastic and inertial properties of that medium.

5 0

2 years ago

Monday Unit test: Ms Nayr's Class:

elena-14-01-66 [18.8K]

1.) 7, humans have the same amount of neck bones. Think of it that way

2.) It has a pattern diamond like or web like.

3.) Indian wild dog

5 0

3 years ago

Read 2 more answers