Answer:
1000N,4.48m/s
Explanation:
Height(h) = 1m
P. E = 1000J
P. E = mass x acceleration due to gravity x height
Acceleration due to gravity = 10m/s
P. E = mgh
Where weight = mg
P. E = weight x height
Weight = P. E / height
Weight = 1000 / 1
Weight. 1000N
b) as he leaves the ground P. E = K. E
P. E = 1/2 mv2
P. E = 1000 , mass = weight / 10
Mass =1000/10 = 100kg
P. E = 1/2 mv2
1000 = 1/2 x 100 x v2
Multiply both sides by 2
1000 x 2 = 100 x v2
V2 = 2000/ 100
V2 =20
Square root both sides
V = square root of 20
V = 4.48m/s
I hope this was helpful, Please mark as brainliest
Answer:
v = 134.06 m/s
Explanation:
Given that,
Radius of a circular track is 1,835 m
Time required to complete one lap around a perfectly circular track is 86 seconds
We need to find the car's velocity. Velocity is equal to,
v=d/t
On circular path,
So, car's velocity is 134.06 m/s.
B: Extension Lines! You could have just searched this up on google
Answer:
b . Move the conductor near a magnet
So power is equal to work over time and work is force times distance, you do 5 times 3 and get 15 dividing by 2 gives us 7.5 W answer c
