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2 years ago

Help plz ASAP !!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Yakvenalex [24]2 years ago

8 0

Answer:

-2

Step-by-step explanation:

Let's solve your equation step-by-step.

−(3v+1)+7(6v+6)=−37

Step 1: Simplify both sides of the equation.

−(3v+1)+7(6v+6)=−37

−3v+−1+(7)(6v)+(7)(6)=−37(Distribute)

−3v+−1+42v+42=−37

(−3v+42v)+(−1+42)=−37(Combine Like Terms)

39v+41=−37

Step 2: Subtract 41 from both sides.

39v+41−41=−37−41

39v=−78

Step 3: Divide both sides by 39.

39v

−78

v=−2

Answer:

v=−2

patriot [66]2 years ago

4 0

Answer:-2

Step-by-step explanation:

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Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

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Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

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Step-by-step explanation:

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1 year ago

Three components are randomly sampled, one at a time, from a large lot. As each component is selected, it is tested. If it passe

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Answer:

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Step-by-step explanation:

The probability of a component passing the test is, P (S) = 0.79.

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Three components are sampled.

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