Brainliest for correct answer
1 answer:
You might be interested in
Answer:
Width = 2
Length = 5
Step-by-step explanation:
let A be the area of the rectangle
L be the length of the rectangle
w be the width of the rectangle
<u><em>Formula</em></u>: ‘<u><em>area of a rectangle</em></u>’
A = L × w
…………………………………………………
A = L × w
⇔ 10 = (w + 3) × w
⇔ 10 = w² + 3w
⇔ w² + 3w - 10 = 0
<u><em>Solving the quadratic equation</em></u> w² + 3w - 10 = 0 :
Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49
then √Δ = 7
-5 is not valid ,because w represents the width
which must be a positive number
Then w = 2
<u><em>Conclusion</em></u>:
Width = 2
Length = 2 + 3 = 5
So it seems as if the first problem is asking this:
.
If x=0.15, then 11/15*(0.15) is 0.11 or 11/100.
The second problem is asking:
To solve algebraically, you want to get rid of the denominators under the x's. To do so, you want to multiply by the Least Common Multiple (LCM) of the denominators. For 3 and 4, the LCM is 12. Multiply everything by 12 to get:
3x+6=4x+2
Now, solve for x
Subtract 4x from both sides:
-x+6=2
Subtract 6 from both sides:
-x=-4
Multiply by -1 on both sides:
x=4.
If x=0.15, then 11/15*(0.15) is 0.11 or 11/100.
The second problem is asking:
To solve algebraically, you want to get rid of the denominators under the x's. To do so, you want to multiply by the Least Common Multiple (LCM) of the denominators. For 3 and 4, the LCM is 12. Multiply everything by 12 to get:
3x+6=4x+2
Now, solve for x
Subtract 4x from both sides:
-x+6=2
Subtract 6 from both sides:
-x=-4
Multiply by -1 on both sides:
x=4.
Answer:
x=12
Step-by-step explanation:
