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2 years ago

Can someone please help? I’ll put u as brainliest (whatever it’s called)

Mathematics

2 answers:

frez [133]2 years ago

7 0

Answer:

Step-by-step explanation:

Tamiku [17]2 years ago

7 0

The answer is C because are of a rectangle is base times height and 8 1/2 x 4 1/2 is 38.25 or 38 1/4

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Log14/3 +log11/5-log22/15=log

Tamiku [17]

Answer:

$log7$

Step-by-step explanation:

when adding logs, apply the log rule: $\log _a\left(x\right)+\log _a\left(y\right)=\log _a\left(xy\right)$

∴ $\log\left(\frac{14}{3}\right)+\log\left(\frac{11}{5}\right)=\log\left(\frac{14}{3}\cdot \frac{11}{5}\right)$

when subtracting logs, apply the log rule: $\log _a\left(x\right)\:-\:\log _a\left(y\right)=\log _a\left(\frac{x}{y}\right)$

$\log\left(\frac{14}{3}\cdot \frac{11}{5}\right)-\log\left(\frac{22}{15}\right)=\log\left(\frac{\frac{14}{3}\cdot \frac{11}{5}}{\frac{22}{15}}\right)\\\\=\log\left(7\right)$

5 0

2 years ago

Read 2 more answers

canstanza has 13 blue envelopes she has 3 fewer yellow envelopes then blue envelopes she has 7 times as many green envelopes as

zavuch27 [327]

She has 93 envelopes in all

8 0

3 years ago

Read 2 more answers

Rewrite x5/6 divided by x1/6 in simplest radical form

lisabon 2012 [21]

5/6 and 1/6 are exponents to X. The X’s are divided by each other. does that make sense?

5 0

2 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

The area of a rectangular gymnasium is (5x+5x) square feet. If it is 5x feet wide, what is the length, in feet?

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

Area = L x W gym area is (5x + 5x) ft² if W = 5x Find the L

Area = L x W divide both sides by W

Area/W = (L x W) / W

Area/W = L = Area/W

L = Area/W

= (5x + 5x) / (5x)

= 5x( 1 + 1) / 5x

= 5x(2) / 5x the 5x's cancel each other 5x/5x = 1

= 2 ft I got 2. I suspect the 12 was a typo and should have been 2

5 0

2 years ago