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3 years ago

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion

Mathematics

1 answer:

Vanyuwa [196]3 years ago

8 0

Answer:

Find the slope of the line that passes through the points shown in the table.

The slope of the line that passes through the points in the table is

Step-by-step explanation:

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How to find the surface area of a prism

Anuta_ua [19.1K]

Answer:

If you are talking about the rectangular prism the equation is

2 × L × W + 2 × L × H + 2 × W × H

If you are talking about Triangular prism the equation is

B × H + L × S + L × B + L × C

5 0

3 years ago

After 2/3 of an hour, the tightrope walker has traveled 1/6 of a mile across Niagara Falls. How many miles will he have to trave

Jlenok [28]

Answer:

1/4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A group of hikers walked 8 and 7/10 miles. And then 5 and 1/5 miles. How far did they walk altogether?

Anton [14]

13 and 9/10 miles altogether

5 0

3 years ago

Can you help me with this problem please

Over [174]

Remark

I think you want us to do both 3 and 4

Three

QR is 4 points going left from the y axis + 2 points going right from the y axis.

QR = 6 units long.

RT is 4 units above the x axis and 3 units below the x axis

RT = 7 units long

TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.

Problem 4

You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.

Area = (b1 + b2)*h/2

Givens

B1 = QR = 6

B2 = UT + TS = 6 + 3 = 9

h = RT = 7

Area

Area = (6 + 9)*7/2

Area = 15 * 7 / 2

Area = 52.5

Comment

You could break this up into a rectangle + a triangle

Find the area of QRTU and add the Area of triangle RTS

Area of the rectangle = L * W

L = RT = 7

W = QR = 6

Area = 7 *6 = 42

Area of the triangle = 1/2 * B * H

B = TS = 3

H = RT =7

Area = 1/2 * 3 * 7

Area = 1/2 * 21

Area = 10.5

Total Area = 42 + 10.5 = 52.5 Both answers agree.

3 0

3 years ago

Find the work (in ft-lb) required to pump all the water out of a cylinder that has a circular base of radius 7 ft and height 200

Virty [35]

Answer:

work done is equal to 384279168 lb-ft

Step-by-step explanation:

The cylinder has a circular base of 7 ft.

The height of the cylinder is 200 ft

The weight density of water in the cylinder is 62.4 lb/ft^3

First, we find the volume of the water in the cylinder by finding the volume of this cylinder occupied by the water.

The volume of a cylinder is given as $\pi r^{2} h$

where, r is the radius,

and h is the height of the cylinder.

the volume of the cylinder = $3.142* 7^{2}*200$ = 30791.6 ft^3

Since the weight density of water is 62.4 lb/ft^3, then, the weight of the water within the cylinder will be...

weight of water = 62.4 x 30791.6 = 1921395.84 lb

We know that the whole weight of the water will have to be pumped out over the height of cylindrical container. Also, we know that the work that will be done in moving this weight of water over this height will be the product of the weight of water, and the height over which it is pumped. Therefore...

The work done in pumping the water out of the container will be

==> (weight of water) x (height of cylinder) = 1921395.84 x 200

==> work done is equal to 384279168 lb-ft

7 0

3 years ago