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Gre4nikov [31]
3 years ago
8

State if the three sides lengths form an acute, obtuse, or right triangle: 7 in, 11 in, 13 in a acute b obtuse c right

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
4 0

Answer:

The triangle with side lengths 7 in, 11 in, 13 in will be an acute angled triangle.

Step-by-step explanation:

If we assume that the triangle with height 7 inches and base 11 inches of a right triangle then its hypotenuse will have the length of

\sqrt{7^{2} + 11^{2}} = \sqrt{170} = 13.04 inches.

But the third side of the triangle is given to be 13 inches which is less than 13.04 inches i.e. 13 < 13.04.

Therefore, the triangle with side lengths 7 in, 11 in, 13 in will be an acute-angled triangle. (Answer)

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Jeremy's car went 300 miles (highway) on 10 gallons of gasoline. What was the average number of miles per gallon?
masya89 [10]
Whenever you see the word "per" you can ALWAYS substitue in the word "divide".  When you see "miles per gallon", change "per" into "divided by" to get miles divided by gallons.  That is how you will solve the problem.

SO.....
300 miles ÷ 10 gallons = 30 miles per gallon
6 0
3 years ago
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Evaluate 2^2⋅4^3=<br><br>Your answer<br><br><br>​
ivanzaharov [21]

Answer:

256

Step-by-step explanation:

First, handle the exponent:

2²=4 (2*2=4)     and     4³=64 (4*4=16*4=64)

Now multiply those two outcomes:

4*64=<u>256</u>

This equation is also known as 4⁴

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3 years ago
7x+14<br> 2x2 + x-6<br> What is the GCF
fenix001 [56]

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6 0
3 years ago
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Eric is studying people's typing habits. He surveyed 525 people and asked whether they leave one space or two spaces after a per
Otrada [13]

Answer: (0.8115, 0.8645)

Step-by-step explanation:

Let p be the proportion of people who leave one space after a period.

Given:  Sample size : n= 525

Number of people responded that they leave one space. =440

i.e. sample proportion: \hat{p}=\dfrac{440}{525}\approx0.838

z-score for 90% confidence level : 1.645

Formula to find the confidence interval :

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

0.838\pm (1.645)\sqrt{\dfrac{0.838(1-0.838)}{525}}\\\\=0.838\pm (1.645)\sqrt{0.00025858285}\\\\=0.838\pm (1.645)(0.01608)\\\\= 0.838\pm0.0265\\\\=(0.838-0.0265,\ 0.838+0.0265)\\\\=(0.8115,\ 0.8645)

Hence, a 90% confidence interval for the proportion of people who leave one space after a period: (0.8115, 0.8645)

3 0
3 years ago
Given that e= 2i – 5j + 9k and f= 8i + 15j + k, find 3f – 2e.
ipn [44]

Plug in "8i + 15j + k" for "f", and "2i – 5j + 9k" for "e"

3(8i + 15j + k) - 2(2i – 5j + 9k)

Distribute 3 to (8i + 15j + k) & - 2 to (2i – 5j + 9k)

3(8i + 15j + k) = 24i + 45j + 3k

-2(2i - 5j + 9k) = -4i + 10j - 18k

-------------------------------------------------------------------------------------------------------------------

Simplify. Combine like terms

24i - 4i + 45j + 10j + 3k - 18k

(24i - 4i) + (45j + 10j) + (3k - 18k)

20i + 55j - 15k is your answer, or (C)

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hope this helps

5 0
3 years ago
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