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GarryVolchara [31]
3 years ago
9

Какая масса хлора и какое количество вещества необходимо для реакции с 12г магния при получении хлорида магния?

Chemistry
1 answer:
Naddika [18.5K]3 years ago
7 0
Mg + Cl₂ = MgCl₂M(Mg) = 24г/моль  m 1 моль Mg = 24 г.По условию задачи дано 12г. Mg  Количество вещества n(Mg) =12÷24=0,5 мольРассуждаем: по уравнению реакции  с 1 моль магния реагирует 1 моль хлора, следовательно с 0,5 моль будет реагировать 0,5 моль хлора.1 моль хлора при н.у. занимает объем 22,4л. , тогда 0,5 моль хлора займет:0,5х22,4л.= 11,2л. Ответ: Для взаимодействии 12 г.  магния потребуется 11,2 л. хлора.
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