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Irina-Kira [14]
3 years ago
10

What is two of same elements is called

Chemistry
2 answers:
svet-max [94.6K]3 years ago
8 0

Answer:

it is a A molecule

Evgesh-ka [11]3 years ago
7 0
It’s a Molecule .......
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Nitrogen ​gas is more abundant in our atmosphere than oxygen! However, nitrogen needs to be converted into different forms to be
Pavlova-9 [17]

Explanation:

(A)role of nittogen fixing bacteria

=Nitrogen-fixing bacteria, microorganisms capable of transforming atmospheric nitrogen into fixed nitrogen (inorganic compounds usable by plants). More than 90 percent of all nitrogen fixation is effected by these organisms, which thus play an important role in the nitrogen cycle.

B)role of nitrifying bacteria

=Nitrifying bacteria convert the most reduced form of soil nitrogen, ammonia, into its most oxidized form, nitrate. In itself, this is important for soil ecosystem function, in controlling losses of soil nitrogen through leaching and denitrification of nitrate.

C)role of denitrifying bacteria

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4 0
3 years ago
12. Which atoms or group of atoms make up the functional group of ethanol (CH3CH2OH)?
Montano1993 [528]

Answer:

Option A. the hydroxyl group (-OH)

Explanation:

Ethanol, CH₃CH₂OH belongs to the class of organic compound called alkanol.

They have general formula as R–OH

Where

R => is an alkyl group

OH => is the hydroxyl group

The hydroxyl group (OH) is the functional group of the alkanol (alcohol)

8 0
2 years ago
This element is less reactive than lithium and magnesium but more reactive than zinc. Which element is this?
Tamiku [17]
The answer should be:

B. Al (Aluminium)
7 0
3 years ago
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What volume of water must be added
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Answer:

litre.50000665432158900643212lo

3 0
3 years ago
A 275 g sample of a metal requires 10.75 kJ to change its temperature from 21.2 oC to its melting temperature, 327.5 oC. What is
Vlada [557]

Answer:

c=0.127\ J/g^{\circ} C

Explanation:

Given that,

Mass of the sample, m = 275 g

It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.

We need to find the specific heat of the metal. The heat required by a metal sample is given by :

Q=mc\Delta T

c is specific heat of the metal

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C

So, the specific heat of metal is 0.127\ J/g^{\circ} C.

4 0
2 years ago
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