Answer:
0.478 M
Explanation:
Let's consider the neutralization reaction between KOH and H₂SO₄.
2 KOH + H₂SO₄ → K₂SO₄ + 2 H₂O
12.7 mL of 1.50 M H₂SO₄ react. The reacting moles of H₂SO₄ are:
0.0127 L × 1.50 mol/L = 0.0191 mol
The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of KOH are 2 × 0.0191 mol = 0.0382 mol
0.0382 moles of KOH are in 80.0 mL. The molarity of KOH is:
M = 0.0382 mol/0.0800 L = 0.478 M
D. there would be a proportional increase in pressure to temperature
Let the ratio of grams of hydrogen per gram of carbon in methane be M, we know that:
M = 0.3357 g / 1 g
Next, lets represent the grams of hydrogen per gram of carbon in ethane be E. The final piece of information we have is:
M / E = 4/3
If we cross multiply,
3M = 4E
Now, substituting the value of M from earlier and solving for E,
E = (3 * 0.3357) / 4
E = 0.2518
There are 0.2518 grams of hydrogen per gram of carbon in ethane.
Un sistema heterogéneo de 3 fases y 1 componente puede ser:
Sólido (hielo)
Líquido (agua)
Gaseoso (vapor)
Answer:
The voltage or potential difference
Explanation:
What makes current flow in a circuit is the voltage or the potential difference.
This force is supplied by the battery or the mains electrical circuit.
- Every circuit requires the voltage to drive current through
- When a circuit is complete, the battery is able to overcome any resistance by the generating enough voltage which is the force to drive the current through.
