The answer is
G = [m1(veca1a2) + m2 (veca3a4) + m3veca5a6)] / (m1 + m2 + m3)
G= m1x5 + m2 x 4sqrt (2) + m3x 3sqrt (2) / 16 = 35 +4 x 3.7x sqrt (2) + 5.3 x3 4sqrt (2) / 16 =35 + 36<span> sqrt (2) / 16
G = 53.09
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The best way too solve it is to cross multiply. When you get the answer tell me and I’ll check it
7s + 20 = 4s -13
7s - 4s = -13 -20
3s = -33
s = -33/3
s = -11
Answer:
Step-by-step explanation:
Statement Reason
1.∠4 is an exterior angle of ΔABC Given
2.∠3 and∠4 form a linear pair Linear pair theorem
3.∠3 is supplementary to ∠4 Property of supplementary angle
4.m∠3+m∠4=180° Definition of supplementary angle
5.m∠1+m∠2+m∠3=180° Triangle sum theorem
6.m∠1+m∠2+m∠3=m∠3+m∠4 From step 4 and 5
7.m∠1+m∠2=m∠4 Subtraction rule