Hamburger is sold for 2 pounds for $4. If Alicia buys 10 pounds of hamburgers, how much will she pay?

Ms. Thomas took her family and friend to the movies. There were a total of 16 people. Children tickets cost $6 and adult tickets

Korolek [52]

Answer:

11 adults

Step-by-step explanation:

First, set up a system of equations:

Let x = number of children and y = number of adults

There is a total of 16 people, so x+y = 16. This is your first equation.

Each child ticket costs $6, so 6x = cost of children's tickets based on the number of children present (x)

Each adult ticket costs $9, so 9y = cost of adult's tickets based on the number of adults present (y)

The total cost of tickets is $129, so 6x+9y = 129. This is your second equation.

Your system of equations is now this:

x + y = 16

6x + 9y = 129

You can solve this system using the method of elimination, where we will eliminate the variable x (number of children), since we are focused on y (number of adults).

Multiply the top equation by -6. This will give the following equation:

-6x - 6y = -96

You can now solve the system of equations by placing the new equation under the second equation like this:

6x + 9y = 129

-6x - 6y = -96

Now, add the two equations together.

6x + (-6x) = 0

9y + (-6y) = 3y

129 + (-96) = 33

After doing this, you get the following equation:

3y = 33

As you can see, the variable x has been eliminated, and you are left with y.

Solve the equation for y:

3y = 33

y = 33/3 = 11

y = 11 adults

5 0

3 years ago

Based on information from Harper’s Index, 37% of adult Americans believe in Extraterrestrials. Out of a random sample of 100 adu

san4es73 [151]

Answer:

z(s) is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

Step-by-step explanation:

We have a prortion test.

P₀ = 37 % P₀ = 0,37

sample size = n = 100

P sample proportion = P = 47 % P = 0,47

confidence interval 95 %

α = 0,05

One tail-test (right tail) our case is to show if sample give enough information to determine if proportion of individual who attended college is higher than the proportion found by Harper´s index.

1.-Hypothesis:

H₀ null hypothesis P₀ = 0,37

Hₐ alternative hypothesis P₀ > 0,37

2.-Confidence interval 95 %

α = 0,05 and z(c) = 1.64

3.-Compute of z(s)

z(s) = [ P - P₀ ] /√(P₀Q₀/n) ]

z(s) = [ ( 0,47 - 0,37 ) / √0.37*0,63/100

z(s) = 0,1 /√0,2331/100 ⇒ z(s) = 0,1 /0,048

z(s) = 2.08

4.-Compare z(s) and z(c)

z(s) > z(c) 2.08 > 1.64

5.-Decision:

z(s) is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

5 0

3 years ago

For A (1, –1), B (–1, 3), and C (4, –1), find a possible location of a fourth point, D, so that a parallelogram is formed using

katrin [286]

The possible coordinates for the vertex D of the parallelogram could be (-4, 3)

It is given that A(1, –1), B (–1, 3), and C (4, –1) are the three vertices of the parallelogram.

Let us assume that the vertices are in the order A, C, B, and D where the coordinates of D are (a, b).

In this scenario, if we join AB and CD, they will become the diagonals of the parallelogram ABCD.

According to the properties of a parallelogram, diagonals bisect each other.

Hence, mid-point of AB = mid-point of CD

Now, according to the mid-point theorem, if mid-point of AB is given as (x,y), then,

x = (x₁ + x₂)/2 and y = (y₁ + y₂)/2

Here, for AC,

x₁ = 1, y₁ = -1

x₂ = -1, y₂ = 3

Then, x = ( 1 - 1)/2 and y = (-1 + 3)/2

(x, y) ≡ (0, 1) ............. (1)

Since (x, y) is also the mid-point of CD, we also have,

x₁ = 4, y₁ = -1

x₂ = a, y₂ = b

Then, x = (4 + a)/2 and y = (-1 + b)/2

(x, y) ≡ ((4 + a)/2, (-1 + b)/2) ................... (2)

From (1) and (2),

(4+a)/2 = 0 and (-1+b)/2 = 1

4+a = 0 and (-1+b) = 2

a = -4 and b = 3

Hence, the fourth vertex D of the parallelogram can be possibly located at (-4, 3)

Learn more about a parallelogram here:

brainly.com/question/1563728

#SPJ1

8 0

1 year ago

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

2 years ago

Use the net to find the surface area of the rectangular prism. A) 48 cm2 B) 120 cm2 C) 384 cm2 D) 432 cm2

Marina86 [1]

Formula: length · width

2 big rectangles:96 + 96 = 192
(12 × 8) · 2

2 smaller rectangles: 72 + 72 = 144
(6 × 12) · 2

2 small rectangles: 48 + 48 = 96
(6 × 8) · 2

Add all 3 numbers:

192 + 144 + 96 = 432

Your answer is D. 432 cm²

Hope this helps :)

6 0

2 years ago