Answer:
the ans is C..... good luck
Answer:
29 :)
it is 29 because 29 falls under all the prime number characteristics
Answer:
The answer is false
Step-by-step explanation:
In a sample above 30 obs like this the confidence interval is defined as
X+- t* (s/sqrt(n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.
To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level
The significance is obtained:
significance = 1 - confidence level = 1 - 0.9 = 0.10
Degrees of freedom (df) for the inteval are
df = n - 1 = 18 - 1 = 17
So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 ( thats the t for 16 df)
Replace all the x values with -3
f(-3)=-2(-3)^2+5(-3)
f(-3)=2(9)-15
f(-3)=18-15
f(-3)=3
Hope I helped :)
Ok so first we do 2 + 3 = 5 * 2 = 10 / by 42 = 4.2
other side 36 - 52 = 16 * 4 = 64 now add 4.2 + 64 = 68.2
