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bixtya [17]
4 years ago
10

How long does it take for an investment to double in value if it is invested at 9 ​% compounded quarterly? Compounded​ continuou

sly?

Mathematics
1 answer:
TEA [102]4 years ago
7 0
Compounded Quarterly
We will calculate $100 growing to $200
Years = log(total/principal) / n*log(1 + rate/n)
For quarterly compounding n = 4
Years = log(200 / 100) / 4 * log (1 + .09/4)
Years = log(2) / 4 * log ( <span><span><span>1.0225 </span> )</span>
</span>Years = 0.30102999566 / (4 * 0.0096633166794)
Years = 0.30102999566 / <span> <span> <span> 0.0386532667 </span> </span> </span>
Years = <span> <span> <span> 7.7879574318 </span> </span> </span>

Compounded Continuously
We will calculate $100 growing to $200
Years = natural log (total/principal) / rate
Years = natural log (200 / 100) / .09
Years = natural log (2) / .09
Years = 0.69314718056 / .09
Years = <span> <span> <span> 7.7016353396 </span> </span> </span>


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If 30,000 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the
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Answer:

The largest possible volume of the box is 500,000 cm³    

Step-by-step explanation:

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let the height of the box, = h

volume of the box, v = hx²

Surface area of the box, A = 4hx + x²

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make h the subject of the formula;

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Volume of the box, V = hx²

V = h*x^2 = (\frac{30000-x^2}{4x} )x^2\\\\V = \frac{30000x^2 -x^4}{4x} \\\\V = \frac{30000x^2}{4x} - \frac{x^4}{4x} \\\\V = 7500x- \frac{x^3}{4}

At maximum value of V, dv/dx = 0

\frac{dv}{dx} = 7500 - \frac{3}{4} x^2\\\\0 = 7500 - \frac{3}{4} x^2\\\\\frac{3}{4} x^2 = 7500\\\\x^2 = 10000\\\\x = \sqrt{10000} \\\\x = 100

Substitute in the value of x to determine the maximum volume, V;

V = 7500x - \frac{x^3}{4} \\\\V = 7500(100) - \frac{1}{4} (100)^3\\\\V = 750000- 250000\\\\V = 500,000 \ cm^3

Therefore, the largest possible volume of the box is 500,000 cm³                  

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Answer:

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Step-by-step explanation:

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