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Fantom [35]
2 years ago
9

Consider three different resistors connected to a battery in parallel.

Physics
1 answer:
zhuklara [117]2 years ago
5 0

Answer:

c) All choices listed are definitely true.

Explanation:

a)

  • As they are connected in parallel, the voltage drop is equal in all the resistors, by definition of a parallel connection, and equal to the terminal voltage of the battery (assuming that the internal resistance of the battery is negligible).

b)

  • Applying Ohm's law to the circuit, we arrive to the following expression:

        I_{tot} = I_{1} +I_{2} + I_{3}  \\  I_{tot} =\frac{V}{Req} = \frac{V}{R_{1}} +\frac{V}{R_{2} }  +\frac{V}{R_{3}}

  • Simplifying common terms, we have:

       \frac{1}{Req} = \frac{1}{R_{1}} +\frac{1}{R_{2} }  +\frac{1}{R_{3}}

  • It can be seen that the equivalent resistance, is less than any of the resistances.

d)

  • Due to the charge conservation principle, as the current is made from moving charges, the sum of the currents passing through these resistors is equal to the current passing through the battery (KCL).
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A lacrosse ball that is thrown straight upwards reaches a maximum height of 4.5 m. At what initial velocity was it thrown? (note
shtirl [24]

Answer:

The initial velocity was 9.39 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

The ball is thrown straight upward with initial velocity u

The ball reaches a maximum height of 4.5 m

At the maximum height velocity v = 0

The acceleration of gravity is -9.8 m/s²

We need to find the initial velocity

The best rule to find the initial velocity is <em>v² = u² + 2ah</em>, where v is

the final velocity, u is the initial velocity, a is the acceleration of

gravity and h is the height

⇒ v = 0 , h = 4.5 m , a = -9.8 m/s²

⇒ 0 = u² + 2(-9.8)(4.5)

⇒ 0 = u² - 88.2

Add 88.2 to both sides

⇒ 88.2 = u²

Take square root for both sides

⇒ u = 9.39 m/s

<em>The initial velocity was 9.39 m/s</em>

5 0
3 years ago
Can somebody help me with this I need to pass
son4ous [18]
<h2>Answer:Radiation-3,Conduction-1,Convection-2</h2>

Explanation:

Radiation is the transfer of heat through electromagnetic waves.

These waves do not require any medium.This is the way we get heat from sun.Radiation is the quickest mode to transfer of heat.

Conduction is the transfer of heat through collisions of atomic particles.

This phenomenon largely occurs in solids like metals.The neighbour atoms sets the atoms into random motion thereby raising the temperature.

Convection is the transfer of heat through actual movement of medium particle.

This phenomenon occurs in gases an liquids.The medium particles actually traverse through the space transferring the heat.

5 0
3 years ago
1. The picture below shows Jamal pushing with a 100-Newton (N) force on a large box. Neither
r-ruslan [8.4K]

Answer:

100 newtons

Explanation:

Given,

Jamal pushing a large box by a force, F = 100 N

Work done on the large box is, W = 0

It is because the applied force is less than the force of the friction between the two surfaces.

Yet, there will be a force that is exerted by the large box on Jamal.

According to newton's third law of motion, every action has an equal and opposite reaction. The reaction force is in the direction opposite to the force of action. But, their magnitude remains the same.

                                        F_{a} =-F_{r}

Hence, If the action force is 100 N, then the reaction force should be in 100 N

4 0
3 years ago
Read 2 more answers
Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. If the charge of object 1 is doubled AND the charge
lbvjy [14]

Answer:

432 units

Explanation:

Let the charges be q and Q separated by a distance r. The electrostatic force , F = kqQ/r² = 72 units. If q = 2q and Q = 3Q, then the new electrostatic force is

F = k × 2q × 3Q/r² = 6kqQ/r² = 6 × 72 = 432 units

5 0
3 years ago
bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s what is the veloci
spin [16.1K]

Answer: V1 = 3.559 - 0.744V2

Explanation: Given that the

bumper car A has

Mass M1 = (281 kg) moving with

Velocity U1 = 2.82 m/s

bumper car B has

Mass M2 = (209 kg) moving with

Velocity U2 = 1.72 m/s

Where U1, U2 are the initial velocity of the two cars

Since the collision is elastic, we will use the formula below,

M1U1 + M2U2 = M1V1 + M2V2

Substitute the values into the formula

281×2.28 + 209×1.72 = 281V1 + 209V2

640.68 + 359.48 = 281V1 + 209V2

1000.16 = 281V1 + 209V2

Make V1 the subject of formula

281V1 = 1000.16 - 209V2

V1 = 1000.16/281 - 209V2/281

V1 = 3.559 - 0.744V2

Therefore, the velocity of car A which

is V1 after the collision will be expressed as V1 = 3.559 - 0.744V2

6 0
3 years ago
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