All categories

3 years ago

Us your understanding of asexual reproduction to explain why is it important that organisms reproduce in a variety of ways.

1 answer:

5 0

The genetic material is identical in asexual reproduction- in order for organisms to be strong they need variety so if a disease comes, some of the species may be able to fight it off because of their varied genetics

You might be interested in

During summer in the northern hemisphere _____.

Kipish [7]

For part of our orbit the northern half of Earth is tilted toward the Sun. This is summer in the northern hemisphere; there are longer periods of daylight, the Sun is higher in the sky, and the Sun's rays strike the surface more directly, giving us warmer temperatures

7 0

3 years ago

The charge of an electron is -1.60x10-19 C. A current of 1 A flows in a wire carried by electrons. How many electrons pass throu

faltersainse [42]

Answer: $6.241\times 10^{18}$ electrons pass through a cross section of the wire each second.

Explanation:

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

Given : Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

To calculate the charge passed we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 1 A

q = total charge = ?

t = time required = 1 sec

Putting values in above equation, we get:

$1A=\frac{q}{1s}\\\\q=1A\times 1s=1C$

When 96500C of electricity is passed , the electrons passed = $6.022\times 10^{23}$

1 C of electricity is passed , the electrons passed = $\frac{6.022\times 10^{23}}{96500}\times 1C=6.241\times 10^{18}$

Hence, $6.241\times 10^{18}$ electrons pass through a cross section of the wire each second.

4 0

3 years ago

An object (mass 12.5 kg) slides on a frictionless surface at 1.32 m/s. How much work must be done to bring the object to rest

mote1985 [20]

Answer:

10.89 J.

Explanation:

The following data were obtained from the question:

Mass (m) = 12.5 kg

Velocity (v) = 1.32 m/s

Work done =?

To obtain the workdone, we shall determine the kinetic energy of the object since work and energy has the same unit of measurement. This is illustrated below:

Mass (m) = 12.5 kg

Velocity (v) = 1.32 m/s

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 12.5 × 1.32²

K.E = 6.25 × 1.7424

K.E = 10.89 J

The kinetic energy of the object is 10.89 J. Hence, the workdone in bringing the object to rest is 10.89 J.

8 0

3 years ago

Climate Change

notsponge [240]