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Vikki [24]
3 years ago
12

Calculate the change in the energy of an electron that moves from the n = 3 level to the n = 2 level. What type of light is emit

ted?
Physics
1 answer:
marissa [1.9K]3 years ago
5 0

Answer:

Red light

Explanation:

The energy emitted during an electron transition in an atom of hydrogen is given by

E=E_0 (\frac{1}{n_2^2}-\frac{1}{n_1^2})

where

E_0 = 13.6 eV is the energy of the lowest level

n1 and n2 are the numbers corresponding to the two levels

Here we have

n1 = 3

n2 = 2

So the energy of the emitted photon is

E=(13.6) (\frac{1}{2^2}-\frac{1}{3^2})=1.9 eV

Converting into Joules,

E=(1.9 eV)(1.6\cdot 10^{-19} J/eV)=3.0\cdot 10^{-19} J

And now we can find the wavelength of the emitted photon by using the equation

E=\frac{hc}{\lambda}

where h is the Planck constant and c is the speed of light. Solving for \lambda,

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{3.0\cdot 10^{-19}}=6.63\cdot 10^{-7} m = 663 nm

And this wavelength corresponds to red light.

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#A

\\ \rm\Rrightarrow H_{max}=\dfrac{u^2sin^2\theta}{2g}

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\\ \rm\Rrightarrow H_{max}=\dfrac{400sin^237}{20}

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\\ \rm\Rrightarrow R=\dfrac{u^2sin2\theta}{g}

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\\ \rm\Rrightarrow T=\dfrac{2(20)sin37}{10}

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\\ \rm\Rrightarrow T=2.4s

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\\ \rm\Rrightarrow v=20-10(2.4)

\\ \rm\Rrightarrow v=20-24

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