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Dmitrij [34]
2 years ago
9

Do all perpendicular lines have negative reciprocal slopes?

Mathematics
1 answer:
inna [77]2 years ago
6 0

Not necessarily, the more correct definition is opposite reciprocal slopes.

The example used is how horizontal and vertical lines are parallel. Horizontal lines have a slope of 0, also written as 0/1. However, vertical lines have an undefined slope, which isn't necessarily negative. It has a slope of 1/0, which is undefined. In this case, the reciprocal isn't negative.

In all other cases (1 and -1, 2 and -1/2, etc.) yes, the perpendicular pairs are negative and reciprocal.

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The x-coordinate of the point (50, 55) is ___________.
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The x-coordinate of the point (50, 55) is 50

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A graph can be defined as a pictorial representation or a diagram that represents data or values.

The distance of point (50, 55) perpendicular to y-axis

Thus, perpendicular distance = 50 units

The x-coordinate of the point (50, 55) is 50

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8 0
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Number 2 i need help
daser333 [38]
The table you drew under the question is exactly the right way to start.

-- Make a second column, next to the 6 and 7.  This column will be
the actual number of each thing.

-- You know that there are 42 marbles, so write '42' in the box
next to the 6, on the 'Marbles' line.
Now you need to figure out what to write in the 'Stones' line, next to the 7. 

--  Look at the 'Marbles' line.  There's a 6 and then a 42.
Ask yourself: "  Self !  What does the 6 have to be multiplied with to get 42 ?" 

-- Whatever the answer is, drop down to the 'Stones' line,
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6 0
3 years ago
What is the probability that in a class of 20 students, 2 of them will have the same birthday?
earnstyle [38]
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8 0
3 years ago
Consider the parabola y = 5x − x2. (a) find the slope m of the tangent line to the parabola at the point (1, 4).
kkurt [141]
The tangent line to a curve is the one that coincides with the curve at a point and with the same derivative, that is, the same degree of variation.
 We have then:
 y = 5x-x²
 Deriving:
 y '= 5-2x
 In point (1, 4)
 The slope is:
 y (1) '= 5-2 * (1)
 y (1) '= 3
 The equation of the line will be:
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 We have then:
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 Rewriting:
 y = 3x-3 + 4
 y = 3x + 1
 Answer:
 the tangent line to the parabola at the point (1, 4) is
 y = 3x + 1
 the slope m is
 m = 3
7 0
3 years ago
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