<h3>
Answer: (x+1)(x+3)</h3>
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Explanation:
Let's assume it factors into (x+a)(x+b)
The goal is to find the two numbers a and b.
FOIL out (x+a)(x+b) to get x^2+(a+b)x+ab
Note how a+b is the middle term and ab is the last term.
In the original expression, 4 is the middle term and 3 is the last term.
So we need to find two numbers that
There are two ways to multiply to 3 and they are
- 1 times 3 = 3
- -1 times -3 = -3
But only the first way has the factors add to 4. So that means a = 1 and b = 3.
Therefore (x+a)(x+b) = (x+1)(x+3)
And x^2+4x+3 = (x+1)(x+3)
Do u need it in inequality form or are we solving for x
Thats figure is made of 2 triangles and 1 rectangle
so we will find the area of triangles and rectangles then add them
Triangle Area=1/2*x/2*2=x/2
multiply by 2 as we have two triangles=2*x/2=x
Area of a rectangle=x*2=2x
Add them=x+2x=14(given area of trepaziod
3x=14
hope i am correct
Answer: x= -9/19
Step-by-step explanation:
5x+18/8=x/4
5x+ 9/4=x/4
5x+9/4-9/4=x/4-9/4
5x= x-9/4
5x(4)=x-9/4(4)
20x=x-9
20x-x=x-9-x
19x=-9
19x/19=-9/19
x=-9/19
X=3 because you subtract the three on both sides to get x alone. So you get: 7x=21 then you divide seven by 21 and get x=3