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elena-s [515]
4 years ago
10

I really need help with this can you please answer the questions and say how you came up with it please I'm begging you

Mathematics
1 answer:
Mamont248 [21]4 years ago
3 0
10 Part A) A= 500(1.03)^2

Part B) well if you use the previous equation in Part A your answer should be $530.45
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What is the midpoint of the line segment wit endpoints (5,6) and (-2,-6)?
Nadya [2.5K]

Answer: 4,5 i think..

7 0
3 years ago
A sequence is defined recursively by the following rules: f(1)=3f(n+1)=2⋅f(n)−1 Which of the following statements is true about
Radda [10]

Answer:

f(2)=5

f(5)=33

Step-by-step explanation:

The given formula, that recursively defines the sequence is

f(1) = 3 \\ f(n + 1) = 2f(n) - 1

When n=1, we obtain;

f(1+ 1) = 2f(1) - 1 \\ f(2) = 2 \times 3 - 1 \\ f(2) = 6 - 1 \\ f(2) = 5

When n=2, we get:

f(2+ 1) = 2f(2) - 1 \\ f(3) = 2 \times 5 - 1 \\ f(3) = 10 - 1 \\ f(3) = 9

When n=3,

f(3 + 1) = 2f(3) - 1 \\ f(4) = 2f(3) - 1 \\ f(4) = 2 \times 9 - 1 \\ f(4) = 18 - 1 \\ f(4) = 17

When n=4

f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33

When n=5,

f(6) = 65

4 0
3 years ago
Anna saves 5/8 of her money. What percent of her money does Anna save?
scoray [572]
 the amnwer is 1.6. all you do is 8 dived by 5

6 0
3 years ago
Read 2 more answers
A. Steven wrote an expression with 2 terms. The second term, which is the whole number 7, is subtracted from the first term. The
bulgar [2K]

Answer:

Part a)

Steve's expression is 2(2x+5)^{2}-7

For x=3, the expression is equal to 235

Part b)

Jasmine's expression is

(3x^{2})+(25x)

For x=2, the expression is equal to 62

Step-by-step explanation:

Part a)

Let

n-----> the first term

The expression is

(n-7)

n=2(2x+5)^{2}

substitute

Steve's expression is

2(2x+5)^{2}-7

Evaluate for x=3

2(2(3)+5)^{2}-7=242-7=235

Part b)

Let

n-----> the first term

Jasmine's expression is

(3x^{2})+(25x)

Evaluate for x=2

(3(2)^{2})+(25(2))=12+50=62

4 0
3 years ago
Can someone please HELP ME!!
IRISSAK [1]

Volume of a cone = PI x r^2 x h/3

Volume = PI x 5^2 x 9/3

Volume = 235.62 cubic cm.

Volume of a block of wax = L x W x H

Volume = 2 x 4 x 3 = 24 cubic cm.

Total number of blocks = Volume of cone / volume of blocks:

235.62 / 24 = 9.82

Round up to 10.

They will need 10 blocks.

4 0
3 years ago
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