Question

A specific distance is approximately 63,500,00 mi. A fly is about 0.18 in. long ???

Answer 1

Answer:

Step-by-step explanation:

a) Given that a specific distance is approximately 6350000 miles.

To write this in scientific notation.  We know that for writing in scientific notation we must writte the given number as a positive number less than 10 x product of powers of n.

Hence this number

6350000 = 6.35 x1000000 = $6.35x10^6$ miles

b) Length of a fly = 0.18 inches.

To write this in scientific notation.  We know that for writing in scientific notation we must writte the given number as a positive number less than 10 x product of powers of n.

so 0.18 = 1.8($1.8(10^{-1}$

c) Given that distance = 5.04x10^9 inches

To line up number of flies required

= $\frac{5.04x10^9}{0.18} = \frac{504x10^9}{18}=28(10^9)\\Answer is\\28(10^9)$