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Vsevolod [243]
3 years ago
6

Find the value of x. Please help me!

Mathematics
1 answer:
Brut [27]3 years ago
6 0

Answer:

Step-by-step explanation:

2

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Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
3 years ago
Factor 3a^2+6ab-24b^2
Monica [59]
(3a²+6ab-24²)= 3a(a+2b)x(4b)
7 0
3 years ago
How do you do these plz help
vichka [17]
Yfsbbffvxukgdfjddf h
4 0
3 years ago
Thе іmagе оf (-2, 5) is (1, 1).
dem82 [27]

Answer:

  (6, -2)

Step-by-step explanation:

To get to x=1 from x=-2, you must add 3 to the x-coordinate. Only one answer choice has an x-coordinate that is 3 more than that of the given point:

  3 + 3 = 6

The image point is (6, -2).

_____

<em>Check</em>

To get from a y-coordinate of 5 to an image point y-coordinate of 1, you must subtract 4. If you subtract 4 from the y-coordinate of (3, 2), you get 2-4 = -2, the y-coordinate in the chosen answer above.

8 0
3 years ago
What is 35% of 60? I need it for studying
seraphim [82]
35% of 60 is 21. Hope this helped!

8 0
4 years ago
Read 2 more answers
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