Question

What are the zeros of the polynomial function f(x)=x^3-x^2-12x

Answer 1

Answer:

{0, 4 and -3}

Step-by-step explanation:

f(x)=x^3-x^2-12x can be factored, starting by taking out the 'x' factor:

f(x)=x^3-x^2-12x = x(x^2 - x - 12), and then by factoring the quadratic:

f(x) = x(x - 4)(x + 3) = 0

Then the zeros are {0, 4 and -3}.

Answer 2

Answer:

The zeros are;

x=-3,x=0, and x=4

Step-by-step explanation:

The given polynomial is

$f(x)=x^3-x^2-12x$

We equate the function to zero to obtain;

$fx^3-x^2-12x=0$

We factor the GCF to get;

$x(x^2-x-12)=0$

We split the quadratic trinomial to get;

$x(x^2-4x+3x-12)=0$

Factor by grouping

$x(x(x-4)+3(x-4))=0$

$x(x-4)(x+3)=0$

The zeros are;

x=-3,x=0, and x=4