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podryga [215]
2 years ago
10

Find all the positive integers less than 1000 that are divisible by 2,3,5 and 7

Mathematics
2 answers:
andre [41]2 years ago
8 0
210, 420,630, 840 multiply of 2*3*5*7
user100 [1]2 years ago
6 0
210, 420, 630, 840
multiples of 2*3*5*7
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I need help on #3, #4,5,6
Stolb23 [73]
It may be 

3.
10x+5y

5(2x)+5(y)

4.
20x-15

5.
-6f-11
6.
-24w+12x


7 0
3 years ago
How do I simplify this ​
Mama L [17]

Answer:

just divide. 729/3 = 243

4 0
3 years ago
Read 2 more answers
Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

Put all the value in equation 1.

41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0
2 years ago
0.86 is 3.06 % of what number (Round to the nearest hundredth.)
polet [3.4K]

Answer:

Let the number be x

3.06% = 0.0306

The above statement is written as

0.0306x = 0.86

Divide both sides by 0.0306

x = 0.86/0.0306

<h2>x = 28.10</h2>

Hope this helps you

4 0
3 years ago
How many ways can you distribute $4$ identical balls among $4$ identical boxes?
Harman [31]

Answer:

5 ways

Step-by-step explanation:

We have to name the cases.

1. 4 - 0 - 0 - 0

2. 3 - 1 - 0 - 0

3. 2 - 2 - 0 - 0

4. 2 - 1 - 1 - 0

5. 1 - 1 - 1 - 1

We don't name 0 - 0 - 1 - 3 or 0 - 1 - 1 - 2 etc. because it is the same thing.

4 0
2 years ago
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