Ask question

Ask question

All categories

Mandarinka [93]

3 years ago

10

Which is an equation of an asymptote of the hyperbola?

1 answer:

-Dominant- [34]3 years ago

7 0

Answer:

idk

Step-by-step explanation:

use photo math to get the answer

You might be interested in

What is the supplement of 179 angel?

chubhunter [2.5K]

<span>For any angle between 0° and 180°, the supplement of <em>the angle</em> is 180° – <em>the angle.</em></span>

<span><em>=> </em>180-179=1</span>

<span>So the supplement of 179 is 1.</span>

<span><em /></span><span>
</span>

6 0

3 years ago

Which choice is equivalent to the quotient below shown here when x>0?

qwelly [4]

Answer:

Choice B is correct

Step-by-step explanation:

The given radical division can be expressed in the following form;

$\frac{\sqrt{16x^{3} } }{\sqrt{8x} }$

Using the properties of radical division, the expression can be expressed in the following form;

$\sqrt{\frac{16x^{3} }{8x} }=\sqrt{2x^{2} }$

Simplifying further yields;

$\sqrt{2x^{2} }=\sqrt{2}*\sqrt{x^{2} }=x\sqrt{2}$

Choice B is thus the correct alternative

5 0

3 years ago

Read 2 more answers

If alvin sold 60% of his baseball cards, gave away 30% of those that were left, and still had 40 baseball cards in his possessio

kipiarov [429]

Answer:

The number of baseball card to begin with is 143

Step-by-step explanation:

Let The number of baseball cards = x

The number of sold baseball card = 60% of x

= 0.6 x

The number of left baseball card = x - 0.6 x = 0.4 x

The number of card gave away = 30 % of left cards

= 0.3 × 0.4 x = 0.12 x

The number of card left in his possession = 40

So, 0.6 x + 0.12 x + 40 = x

Or, 40 = x - 0.6 x - 0.12 x

Or, 40 = 0.28 x

∴ x = $\frac{40}{0.28}$ = 142.85 ≈ 143

Hence The number of baseball card to begin with is 143 Answer

3 0

3 years ago

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

2 years ago

What is 0.366 in expanded notation

oksano4ka [1.4K]

3 × 1/10 + 6 × 1/100 + 6 × 1/1000
I'm pretty sure that's it but I'm not good at math

4 0

3 years ago