False
because tan^2 45 = 1^2 = 1
and sec^2 x = 1/ cos^2 45 = (sqrt2)^2 = 2
so the sum = 3
<h2>
The area of the framed photograph = 1156 
</h2>
Step-by-step explanation:
Given,
The length of photograph (l) = 14 inches and
The breadth of photograph (b) = 10 inches
To find, the area of the framed photograph = ?
We know that,
The area of the framed photograph = (l + 2b)(l + 2b)
= (14 + 2 × 10) (14 + 2 × 10) 
= (14 + 20) (14 + 20) 
= (34) (34) 
= 1156 
∴ The area of the framed photograph = 1156 
16.004 = (1 x 10) + (6 x 1) + (0/10) + (0/100) + (4/1000)
Hope this helps ;)
Answer:
2
Step-by-step explanation:
Next time, please include the instructions.
This inequality could be broken into two parts:
4m

m + 9 AND m + 9 > -9 + 4m
Focus first on the inequality m + 9 > -9 + 4m. subtract m from both sides, obtaining:
9 > -9 + 3m. Next, add 9 to both sides, obtaining: 18>3m, or m<6
Last step: Determine whether the inequality <span>4m≥m+9 is true if m<6.</span>