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BartSMP [9]
2 years ago
14

Select the equations of f the lines that are parallel to the lines whose equations is y=3x+5

Mathematics
1 answer:
saw5 [17]2 years ago
5 0

Answer:

<h2>y = 3x + b where b is any real number</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

We have the equation: y=3x+5

Parallel lines have the same slope. Therefore the equation of the lines that are parallel to the given line if in form:

y=3x+b

where b is any real number.

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HELP PLEASE IM STUCK!
Artist 52 [7]

Answer:

b) f(x) = x + 6

Step-by-step explanation:

The coordinate (0, 6) makes the y-intercept = 6. Only one of these functions has that intercept: f(x) = x + 6. If you plug in each coordinate the outputted y-value matches up, making this the right answer.

7 0
2 years ago
Three stamps can be attached to each other in various ways.how many ways might three stamps be attached?
ivanzaharov [21]
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula. 
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C. 
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space. 
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.


8 0
3 years ago
Please help me my brain is so fried rn.
stiv31 [10]
My brain is too whyyy
8 0
2 years ago
Ive been staring at this for a long time now, pls help<br>​
Luba_88 [7]

Answer:

9

Step-by-step explanation:

I replaced the missing variable with x and solved the equation from there.

6 0
2 years ago
Read 2 more answers
Jessica wrote 6 6 6 on the board. what is another way to show 6 6 6 6
Ray Of Light [21]
Umm she could put 6 times 4
5 0
3 years ago
Read 2 more answers
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