E(X) = 0(0.7) + 1(0.2) + 2(0.1) = 0.2 + 0.2 = 0.4
The expected daily loss due to blackouts = 0.4 * $500 = $200
Var(X) = 0(0.7 - 0.4)^2 + 1(0.2 - 0.4)^2 + 2(0.1 - 0.4)^2 = 0.04 + 0.18 = 0.22
The expected daily variance due to blackouts = 0.22 * $500 = $110
Answer:
8
Step-by-step explanation:
Answer:
x positive, y negative
Step-by-step explanation:
-60 is the 4th quadrant of the unit circle ( negative angles go clockwise from 0), so the x value is positive and the y value is negative.
Let's Simplify X to equal 1 by dividing by 100. then we divide 420 by 100 to get 4.2, so y=4.2 when x=1, we then multiply by each by 11.
y = 46.2
x = 11
The answer would be $175
Multiply the most by the number of tickets
