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3 years ago

Find the area and perimeter of the algebra titles don't forget your units

Mathematics

1 answer:

Rufina [12.5K]3 years ago

8 0

The perimeter of the large square is 24 and the area is 36 units
the perimeter of the small squares are 4 and the areas are 1 unit.
All together the perimeter is 29 and the area is 38.

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Can someone help me please

Lisa [10]

Answer:

perimeter is 12x-6

Step-by-step explanation:

perimeter is the sum of all sides

3(x+2) + 2x+11 + 7x-23

distribute the 3 in the first term, then combine 'like terms'

3x+6 + 2x+11 + 7x-23

3x+2x+7x + 6+11+(-23)

12x-6

4 0

2 years ago

Read 2 more answers

Find the equation of the tangent line. y=(x^2+x-2)^2 at (-1,4)

Keith_Richards [23]

Compute the derivative of y = (x² + x - 2)² using the chain rule:

dy/dx = 2 (x² + x - 2) d/dx [x² + x - 2]

dy/dx = 2 (x² + x - 2) (2x + 1)

Evaluate the derivative at x = -1 :

dy/dx (-1) = 2 ((-1)² + (-1) - 2) (2 (-1) + 1) = 4

This is the slope of the tangent line to the function at (-1, 4).

Use the point-slope formula to get the equation for the tangent line:

y - 4 = 4 (x - (-1)) → y = 4x + 8

6 0

3 years ago

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in 4th quadrant so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

3 years ago

I just don't know where to start. I'm doing Algebra 2 stuff with sohcahtoa.

mezya [45]

Hello!

As you can see, 22 is the opposite angle. We are looking for the adjacent angle. Let's just call it x. Using SOH CAH TOA, we see that the tangent is the opposite divided by the adjacent side. Let's use that.

tan54≈1.38

This gives us the equation below.

1.38=22/x

Let's solve this equation for x.

1.38x=22

x=22/1.38

x=15.94

Therefore, the length of the shadow is about 15.94 meters.

I hope this helps!

7 0

3 years ago

Read 2 more answers

Item 10

Rina8888 [55]

How much are the soccer cleats

7 0

3 years ago