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3 years ago

I need help I'm failing plzzzzz god bless you!

Mathematics

2 answers:

ryzh [129]3 years ago

8 0

Answer:

Step-by-step explanation:

bearhunter [10]3 years ago

7 0

Answer:

Uhm I don’t see what u need help with?

Step-by-step explanation:

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a 51 foot ladder is leaning up against a building. the top of the ladder reaches the wall at a height of 50 feet. How far is the

almond37 [142]

1 foot i think
i might be very wrong

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3 years ago

How do you divide decimals 10.305 divided by2.5?

Rainbow [258]

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$10.305 \div 2.5 =$

$10.305 \div \frac{10}{4} = \\$

$10.305 \times \frac{4}{10} = \\$

$\frac{10.305 \times 4}{10} = \\$

$\frac{41.220}{10} = \\$

$4.1220$

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3 0

3 years ago

A triangle has an area 14.5 ft.². The base of a triangle is 8 feet. What is the height?

Virty [35]

Answer:

The height is 3.625ft.

Step-by-step explanation:

0.5x8xa=14.5

4a=14.5

a=14.5/4=3.625

7 0

3 years ago

Pls help me out................................

lana66690 [7]

Answer:

The point 6,60 means that in a timespan of 6 hours they were able to build 60 cars

Step-by-step explanation:

5 0

3 years ago

1. Find four consecutive even integers such that the sum of the first and third is 6 less than the largest

Sophie [7]

These are indeed quite a lot of exercises, but a lot of them are almost identical - only small computations will change. So, I'm glad to help you with one exercise from every cathegory, but I encourage you to solve the others on your own.

<h2>Exercise 1</h2>

You can call four consecutive integers as

$x,\ x+1,\ x+2,\ x+3$

So, the sum of the first and third is $x+(x+2) = 2x+2$

We want this quantity to be six less than the largest, i.e. $(x+3)-6 = x-3$

So, the equality is

$2x+2 = x-3$

Subtract x from both sides:

$x+2 = -3$

Subtract 2 from both sides:

$x = -5$

So, the consecutive integers are

$-5,\ -4,\ -3,\ -2$

In fact, the sum of the first and third is $-5-3 = -8$ , which is indeed six less than the largest: $-8 = -2-6$

<h2>Exercise 2</h2>

If you call the first odd number $x$ , the next consecutive odd numbers will be $x,\ x+2,\ x+4,\ x+6$

In fact, we have to count skipping two's, because we only want odd integers. From here, you go on like exercise 1: you write the largest (which is x+6), and set it to be two more than the sum of the other three (x, x+2 and x+4)

<h2>Exercise 3</h2>

By the same logic of exercise 2, two consecutive even integers are $x,\ x+2$ , assuming that x is even.

So, you set the equation as usual: the smaller (which is x) is 26 less than three times the larger (which means 3(x+2)-26)

<h2>Exercise 4 to 8</h2>

These are all pretty identical to exercise 1: you start by listing three or four consecutive integers:

$x,\ x+1,\ x+2\quad\text{or}\quad x,\ x+1,\ x+2\ x+3$

and then you translate the request of each exercise accordingly. Remember that expressions like "three times the second number" means that you have to multiply: $3(x+1)$ , while expression like "six more than the first" or "thirteen less than the first" imply adding/subtracting: $x+6$ or $x-13$ .