Answer:
200.
Step-by-step explanation:
0-49=round down 50-99=round up.
The slope is an expression of the change in y after a change in x.
Usually, this is expressed with a ratio, with the difference in y first.
The formula for slope is written as
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
.
Our points are
![(x_1,\ y_1)](https://tex.z-dn.net/?f=%28x_1%2C%5C%20y_1%29)
and
![(x_2,\ y_2)](https://tex.z-dn.net/?f=%28x_2%2C%5C%20y_2%29)
.
Of course, the difference is just subtracting one from the other, but you'll get either a positive or negative value depending on which way you subtract. That's all fine and dandy if you handle the differences in x and y in the same way like in the formula, because any unwanted negatives get cancelled out...it's not important.
Anyways, let's plug our points (2, 8) and (6, 12) into the slope formula.
![\frac{12-8}{6-2}=\frac{4}{4}=\frac{1}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B12-8%7D%7B6-2%7D%3D%5Cfrac%7B4%7D%7B4%7D%3D%5Cfrac%7B1%7D%7B1%7D)
Any number divided by 1 stays the same, so we can leave out the /1 and just have our slope be
1.
Hi there,
θ = 180º + the angle of the right-angled triangle.
For finding the angle we know that the opposite side measures 6 units and the adjacent side measures 8 units. So, the hypotenuse is 10 units.
If we want to find the angle of the right-angled triangle we have to use the following equation.
sin(the angle of the right-angled triangle) = ![\frac{6}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D)
⇒ the angle of the right-angled triangle =
≈ 36,87º
So,
θ = 180º + the angle of the right-angled triangle
θ ≈ 180º + 36,87º
θ ≈ 216,87º
sin(θ) = sin(216,87º)
sin(θ) =
sin(θ) = ![\frac{-3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B-3%7D%7B5%7D)
If you want to do it using properties:
θ = 180º + |the angle of the right-angled triangle|
⇒ sin(θ) = sin(180º + |the angle of the right-angled triangle|)
Using properties:
⇒ sin(θ) = sin(180º)*cos( |the angle of the right-angled triangle|) + cos(180º)*sin(|the angle of the right-angled triangle|)
Sin (180) = 0
⇒ sin(θ) = cos(180º)*sin(|the angle of the right-angled triangle|)
sin(the angle of the right-angled triangle) = -![\frac{6}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D)
And cos(180º) = -1
⇒ sin(θ) = -1* ![\frac{6}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D)
⇒ sin(θ) =
⇒ sin(θ) = ![\frac{-3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B-3%7D%7B5%7D)
W(-4,7); X(-2,1); Y(2,1); Z(4,4)
Answer:
the first choice
Step-by-step explanation:
0.25= 0.25
2/3= 0.3333333
56%= 0.56
0.25<0.33<0.56