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3 years ago

show me how to solve: 110 calories in 28.4 grams of cereal, how many calories in 34.08 grams of cereal?

Mathematics

1 answer:

algol [13]3 years ago

7 0

Answer:

132 calories

Step-by-step explanation:

Find the rate or how many calories in 1 gram of cereal, use x as the # of calories for 1 g

28.4x = 110

Divide both sides by 28.4 - x≈3.873239... cal (rounded to hundredths is 3.87)

Multiply 34.08 by 3.87: 132 calories

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When deriving the quadratic formula by completing the square, what expression can be added to both sides of the equation to crea

nignag [31]

The expression that would be added to both sides is (b/2a)^2

<h3>How to determine the expression?</h3>

The equation is given as:

x^2 + b/ax + __ = c/a + __

Take the coefficient of x

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Divide by 2

b/2a

Square the expression

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Hence, the expression that would be added to both sides is (b/2a)^2

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1 year ago

Assume f(x) = g(x). Which of the following pairsof functions may be used to represent theequation 3^x+^2 = 7x + 6?

Aloiza [94]

Functions and equations

We have that:

$3^{x+2}^{}=7x+6$

Let's name each side of it with f(x) and g(x):

Then, we have that:

$\begin{gathered} f(x)=3^{x+2} \\ \text{and} \\ g\mleft(x\mright)=7x+6 \end{gathered}$

Then, the answer is C

<h2>Answer: C</h2>

4 0

1 year ago

f(x)=(2x−3)(x+6)(5x+6)f, left parenthesis, x, right parenthesis, equals, left parenthesis, 2, x, minus, 3, right parenthesis, le

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Step-by-step explanation:

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2 years ago

Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

7 0

3 years ago

Kalvin sells bottles of water at baseball games he pays 0.75 per bottle and 3.78 for the ice to keep cold let b represent the nu

sergij07 [2.7K]

Answer:

3.78+.75b=c

Step-by-step explanation:

7 0

3 years ago

show me how to solve: 110 calories in 28.4 grams of cereal, how many calories in 34.08 grams of cereal?​

show me how to solve: 110 calories in 28.4 grams of cereal, how many calories in 34.08 grams of cereal?