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skelet666 [1.2K]
3 years ago
5

What is 4x-2+x=-2+2x

Mathematics
1 answer:
Vsevolod [243]3 years ago
4 0

Answer:

x= no solution

Step-by-step explanation:

4x-2+x=-2+2x

We first add 4x+x on the left side.

5x-2=2+2x

We then add 2 to both sides.

5x=2x

The answer is no solution because we got no answer out of the equation.

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The point (-4‚-2) lies on a circle. What is the length of the radius of this circle if the center is located at (-8‚-10)
MAVERICK [17]

Answer:

<em>4√5</em>

Step-by-step explanation:

The length of the radius of the circle will be the distance between the two coordinates. Using the formula:

D = √(x₂-x₁)²+(y₂-y₁)²

Given the coordinates (-4‚-2) and (-8‚-10)

R = √(-8-(-4))²+(-10-(-2))²

R = √(-4)²+(-8)²

R = √16+64

R = √80

R = √16*5

R = 4√5

<em>Hence the  length of the radius of this circle is 4√5</em>

5 0
3 years ago
Which of the following expressions can be combined?
Rom4ik [11]

Answer:  Choice C

Work Shown:

2\sqrt{12} - 6\sqrt{27}\\\\2\sqrt{4*3} - 6\sqrt{9*3}\\\\2\sqrt{4}*\sqrt{3} - 6\sqrt{9}*\sqrt{3}\\\\2*2*\sqrt{3} - 6*3*\sqrt{3}\\\\4\sqrt{3} - 18\sqrt{3}\\\\(4-18)\sqrt{3}\\\\-14\sqrt{3}\\\\

In short,

2\sqrt{12} - 6\sqrt{27}=-14\sqrt{3}

3 0
2 years ago
Given PQRS is a square, solve for x.
ivanzaharov [21]

Answer:

x = 11

Step-by-step explanation:

The angles in a square are right , that is 90°

The diagonals bisect the angles , then

6x - 21 = 45 ( add 21 to both sides )

6x = 66 ( divide both sides by 6 )

x = 11

7 0
3 years ago
Read 2 more answers
Doreen lives 3/4 miles from the library. If Sheila lives 1/2 as far away as Doreen, which statement is true?
Lena [83]

Answer:

A. Sheila lives closer to the library

Step-by-step explanation:

8 0
4 years ago
A=(-2,-7) B=(-6,4) C=(-2,7) D=(2,4) What is the perimeter?
Nata [24]

 

\displaystyle\bf\\AB=\sqrt{\Big(-6-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AB=\sqrt{\Big(-6+2\Big)^2+\Big(4+7\Big)^2}\\\\AB=\sqrt{\Big(-4\Big)^2+\Big(11\Big)^2}\\\\AB=\sqrt{16+121}\\\\\boxed{\bf AB=\sqrt{137}}

.

\displaystyle\bf\\BC=\sqrt{\Big(-2-(-6)\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(-2+6\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(4\Big)^2+\Big(3\Big)^2}\\\\BC=\sqrt{16+9}\\\\BC=\sqrt{25}\\\\\boxed{\bf BC=5}

.

\displaystyle\bf\\CD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(2+2\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(4\Big)^2+\Big(-3\Big)^2}\\\\CD=\sqrt{16+9}\\\\CD=\sqrt{25}\\\\\boxed{\bf CD=5}

.

\displaystyle\bf\\AD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AD=\sqrt{\Big(2+2\Big)^2+\Big(4+7\Big)^2}\\\\AD=\sqrt{\Big(4\Big)^2+\Big(11\Big)^2}\\\\AD=\sqrt{16+121}\\\\\boxed{\bf AD=\sqrt{137}}

.

\displaystyle\bf\\P=AB+BC+CD+AD=\sqrt{137}+5+5+\sqrt{137}\\\\\boxed{\bf P=10+2\sqrt{137}}

 

4 0
3 years ago
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