Let's actually find the line of best fit...
m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)
m=(11*836-130*55)/(11*385-3025)
m=2046/1210
m=93/55
b=(Σy-93Σx/55)/n
b=(55Σy-93Σx)/(55n)
b=(7150-5115)/(55*11)
b=185/55, so the line of best fit is:
y=(93x+185)/55
A) The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.
Which means that those who do not practice at all will win about 3.36 times
B) y(13)=(93x+185)/55
y(13)≈25.34
So after 13 months of practice one would expect to win about 25.34 times.
Answer:
Step-by-step explanation:
first pic
Statement. Reasons
1. AC is congruent to 1.Given
HF
2.BC is congruent to. 2. Given
FE
3. Measure angle ACB. 3. Right angles are congruent
is congruent to Measure
angle HFE
4. Triangle ABC is
congruent to Triangle HEF 4. SAS, side angle side
second pic
statement. reason
1.Angle K is congruent 1. Given
to angle M
2.KL equals ML. 2. Given
3.Measure angle KLJ. 3.Vertical angles are congruent
is congruent to Measure
angle MLP
4Triangle JKL is congruent. 4. ASA, angle side angle
to triangle PML
third pic
statement. reason
1. Already stated. 1. Already stated
2 PT congruent to RS. 2. Given
3. Angle PQT congruent 3. Verticle angles are congruent
to Angle RQS
4. trianlge PQT is congruent to Triangle RQS. 4. ASA, angle side angle
( hope this helps! )
Answer:
- 1 1/14 seconds
- 4 2/7 seconds
Step-by-step explanation:
We are being asked for times, so we can express the rate in terms of seconds per meter.
(15 seconds)/(14 meters) = (15/14) seconds per meter = 1 1/14 seconds/meter
__
1) It will take Robot A 1 1/14 seconds to go 1 meter.
2) it will take Robot A 4 2/7 seconds to go 4 meters. (4 times as long)
Answer:
Step-by-step explanation:
What did you include in your response? Check all that apply.
There would be an open circle at (2, 1). <u>Yes</u>
There would be a closed circle at (2, 3). <u>Yes</u>
There would be an open circle at (4, 3). <u>Yes</u>
There would be a closed circle at (4, −4). <u>Yes</u>
Endpoints that are not included in the domain of a particular piece of a function are represented by an open circle. <u>Yes</u>
