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3 years ago

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Mathematics

1 answer:

sergiy2304 [10]3 years ago

7 0

Answer: I believe it is B

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muminat

The area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = $\frac{1}{2}\times \pi r^2$

$$=\frac{1}{2}\times \pi\times 4^2$

$$=\frac{1}{2}\times \pi\times 16$

Area of the semi-circle = $$8\pi$ cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

$AC^2+BC^2=AB^2$

$AC^2+4^2=8^2$

$AC^2=64-16$

$AC^2=48$

$AC=4\sqrt{3}$ cm

Base of the triangle ABC = $4\sqrt{3}$ cm

Height of the triangle = 4 cm

Area of the triangle ABC = $\frac{1}{2}\times b \times h$

$$=\frac{1}{2}\times 4\sqrt{3} \times 4$

Area of the triangle ABC = $8\sqrt{3}$ cm²

Area of the shaded region

= Area of the semi-circle – Area of the triangle ABC

= $$8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2$

= $$8(\pi \ -\sqrt{3})\ \text{cm}^2$

Hence the area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

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2 years ago

What is the measure of angle gxi?

makvit [3.9K]

Answer:

Step-by-step explanation:

4 0

3 years ago

if sweet t repeats 200 times, about how many shells can he expect to be green ? the answers are 120 shells ,12 shells , 60 shell

guajiro [1.7K]

Its 60 shells because if u multiply 325 by 60 green shells therefore its 60 because u cant multiply each time of green shells

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3 years ago

What are all the real zeros of y=(x-12)^3-10

Daniel [21]

Domain of (x-12)3-10
Range of (x-12)3-10
Parity of (x-12)3-10
Axis Interception point's of (x-12)3-10
x intercepts (40/3) Y Intercept (0,-46)
Inverse of (x -12)3-10: [x+46/3]

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3 years ago

Read 2 more answers

If ab =9cm and bc =12 cm which does ac equal

Rama09 [41]

Just add them together
9 + 12 = 21

5 0

3 years ago