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3 years ago

What is the remainder in the synthetic division below?

Mathematics

2 answers:

nydimaria [60]3 years ago

7 0

The answer is C: three

sveticcg [70]3 years ago

3 0

Answer:

Step-by-step explanation:

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0.5s +1=7 + 4.5s S =

kvv77 [185]

Answer:

$s = -\frac{3}{2}$

Step-by-step explanation:

Solve for the value of $s$ :

$0.5s + 1 = 7 + 4.5s$

-Combine both $0.5s$ and $4.5s$ by subtracting $0.5s$ by $4.5s$ :

$0.5s + 1 - 4.5s = 7 + 4.5s - 4.5s$

$-4s + 1 = 7$

-Subtract $1$ to both sides:

$-4s + 1 - 1 = 7 - 1$

$-4s = 6$

-Divide both sides by $-4$ :

$\frac{-4s}{-4} = \frac{6}{-4}$

$s = -\frac{3}{2}$

So, the value of $s$ is $-\frac{3}{2}$ .

3 0

3 years ago

Paid wages Rs.6000 and still outstanding Rs.4000

Firlakuza [10]

The answer is Rs.2000

6 0

3 years ago

Help please help me its a hard one

DanielleElmas [232]

Answer:

The sum of a and b is 12.

Step-by-step explanation:

Try drawing this figure. ABCD would actually be a triangle, rather than the common quadrilateral you would expect - considering there are 4 points plotted. Therefore, we would have to find the distance between respective points ( 0, 1 ) and ( 2, 5 ) / ( 2, 5 ) and ( 7, 0 ) / ( 0, 1 ) and ( 7, 0 ). Let's apply the distance formula and calculate the distance between each point, therefore determining the perimeter.

Distance between points ( 0, 1 ) and ( 2, 5 )

= $\sqrt{(2-0)^2+(5-1)^2}$

= $\sqrt{(2)^2+(4)^2}$

= $\sqrt{4+16}$

= $\sqrt{20}$ = $2\sqrt{5}$

Distance between points ( 2, 5 ) and ( 7, 0 )

= $\sqrt{(7-2)^2+(0-5)^2}$

= $\sqrt{5^2+(-5)^2}$

= $\sqrt{25+25}$

= $\sqrt{50}$ = $5\sqrt{2}$

And you can calculate the distance between points ( 0, 1 ) and ( 7, 0 ) to be exactly $5\sqrt{2}$ as well. Therefore, you can say that the perimeter of this triangle is $2(5\sqrt{2}) + 2\sqrt{5}$ = $10\sqrt{2} + 2\sqrt{5}$ . Note that this is similar to the form we are given. Thus, a = 10, and b = 2 - making it's sum 10 + 2 = 12.