Answer:
y = m x + b equation of a straight line
m m' = -1 condition for perpendicular lines
If y = 4 x - 7 then m = 4 so m' = -.25
Y = -.25 X + A we need to find A
A = Y + .25 * 8 = 2 + 2 = 4
Y = -.25 X + 4
Check:
2 = -.25 * 8 + 4 = -2 + 4 = 2
Answer: The answer is 1296
Answer:
-3 + x^2
Step-by-step explanation:
8+x^2-11
First combine the like terms.
so..
8-11 = -3
= -3 + x^2
but we don't know the value of x so we just leave it as it is.
And they both are not like terms so we cant solve them together so you stop there
Hope that helped!
The perpendicular line to x-6y=2, and passing through (2, 4) is y=-6x+16
