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3 years ago

HELP ME PLEASE QUICK PLEASE PLSPSPSPSLSLSS

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

4 0

Answer:

1. 55

2. 55-85

3. 95

4. i dont

know5. it makes it odder.

Step-by-step explanation:

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What's the answer to the picture below

romanna [79]

9514 1404 393

Answer:

B. √900

Step-by-step explanation:

The solutions to the equation are ...

x = ±√900 = ±3√100 = ±10√9 = ±30

Of the offered choices, the only one that matches any of these is ...

√900

6 0

3 years ago

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

3 years ago

Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC.<br> Prove △GEC ≅ △HFA.

sergejj [24]

Already answered here: brainly.com/question/26860297

8 0

2 years ago

Read 2 more answers

I need help! I'm running out of coins!!!

Law Incorporation [45]

Answer:

4) m∠F ≈ 67°

5) m∠x ≈ 53°

6) m∠? ≈ 16°

Step-by-step explanation:

(It's not letting me post, so I'll attach screenshots:)

8 0

3 years ago

Factor the expression below so it is in simplest form.<br> 8(3x + 5) + 14

shtirl [24]

Answer:

24x+54

Step-by-step explanation:

8(3x+5)= 24x+40

24x+40+14=24x+54

24x+54

8 0

3 years ago

Read 2 more answers