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Licemer1 [7]
3 years ago
9

The midpoint of AB is M(4, -1). If the coordinates of A are (2,5), what are the

Mathematics
2 answers:
ozzi3 years ago
8 0

Answer:

(6,-7)

Step-by-step explanation:

take b as x2,y2

then apply mid point formula

x=(x1+x2)/2

y=(y1+y2)/2

tia_tia [17]3 years ago
6 0

Answer:  B = (-6, 7)

<u>Step-by-step explanation:</u>

Given: M = (4, -1)    A = (2, 5)

M_x=\dfrac{A_x+B_x}{2}\qquad \qquad \qquad M_y=\dfrac{A_y+B_y}{2}\\\\\\4=\dfrac{2+B_x}{2}\qquad \qquad \qquad -1=\dfrac{5+B_y}{2}\\\\\\8 = 2+B_x\qquad \qquad \qquad\quad -2=5+B_y\\\\\\6=B_x\qquad \qquad \qquad\qquad \quad -7=B_y

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Determine the range of the function.
Naya [18.7K]

Answer:

Solution: f(x)\ge-5\\Interval:[-5,\infty)

Step-by-step explanation:

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3). x_v=-\frac{b}{2a}

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4 0
3 years ago
If m∠ATB = 20°, m∠BTD = 72°, and m∠CTD = 38°, what is m∠ATC?
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Step-by-step explanation:

Ok, we know that:

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m∠ATD = m∠ATB + m∠BTD = 20° + 72° = 92°

Now, we also know that m∠CTD = 38°

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3 years ago
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Answer:

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dangina [55]

Answer:

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Step-by-step explanation:

GCF, multiply all the prime factors common to both numbers:

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3 0
2 years ago
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