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bonufazy [111]
1 year ago
12

Find the value of x in the triangle

Mathematics
2 answers:
lianna [129]1 year ago
7 0

Answer:

x = 29 degrees

Step-by-step explanation:

We know that all of the angles inside of a right triangle add up to 180. We also know that a right angle is 90 degrees. We can do 61 + 90 = 151. 180 - 151 = 29. This means that x = 29 degrees.

goldenfox [79]1 year ago
3 0

Answer:

<h2><u><em>29°</em></u></h2>

Step-by-step explanation:

the sum of the interior angles in a triangle is 180°

from the picture you have 1 angle of 90° and 1 angle of 61°, sum and you find the "x".

180 - 90 - 61 = 29°

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32-7 (6+12) divided by 4 to the power of 2.<br><br> Brainliest
Leni [432]

Answer:

Step-by-step explanation:

32 - 7(6+12) / 4^2

25 + 18 /4^2

43 / 16

2.6875 when you round it you get 2.7

8 0
2 years ago
HURRY!!
vovikov84 [41]

Step-by-step explanation:

-0.5x >= 4

x <= -8 (divide by -0.5, flip the inequality sign)

Hence the correct number line is the 2nd one.

4 0
2 years ago
Using the law of cosines, what is m&lt;X<br> 61, 79, 82, 91
joja [24]
Answer: 79°


Explanation:


1) Law of cosines:


In a triangle with sides a, b, c whose opposite angles are, respectively, A, B and C, the law of cosines states:

c² = a² + b² - 2 a×b×cos (C)

2) In the triangle of the figure you have

c = 9
C = X
a = 6
b = 8
⇒ 9² = 6² + 8² - 2(6)(8) cos(X)
⇒ 81 = 36 + 64 - 96cos(X)
⇒ 96cos(X) = 36 + 64 - 81 = 19
⇒ cos(X) = 19 / 96 
⇒ X = arccos(19/26) = 78.6° ≈ 79°

5 0
2 years ago
In $\triangle pqr$, we have $pq = qr = 34$ and $pr = 32$. point $m$ is the midpoint of $\overline{qr}$. find $pm$.
LekaFEV [45]

In triangle PQR, by the law of cosines we have

34^2=32^2+34^2-2\cdot32\cdot34\cos(m\angle PQR)\implies\cos(m\angle PQR)=\dfrac8{17}

In triangle PMQ, we have

PM^2=32^2+17^2-2\cdot32\cdot17\cos(m\angle PQR)\implies PM^2=801\implies PM=\boxed{3\sqrt{89}}

5 0
3 years ago
The functoin f has zeros at -3 and 4 witch graph could represent function f
IRINA_888 [86]

<u>Since I don't see the graphs</u>:

 ⇒ I am going to answer by the general format of what you should see

<u>The function has zeros at -3, 4</u>:

 ⇒ which means that the function must interest the x-axis at x = -3 and

      x = 4

Hope that helps!

      ⇒look at the image I uploaded which shows a possible answer

7 0
2 years ago
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