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timama [110]
3 years ago
5

Scallops use jet propulsion to move from one place to another. Their shells make them denser than water, so they normally rest o

n the ocean floor. If a scallop wishes to remain stationary, hovering a fixed distance above the ocean floor, it must eject water _____ so that the thrust force on the scallop is _____.
Physics
2 answers:
bonufazy [111]3 years ago
8 0

Answer:

Scallops use jet propulsion to move from one place to another. Their shells make them denser than water, so they normally rest on the ocean floor. If a scallop wishes to remain stationary, hovering a fixed distance above the ocean floor, it must eject water <u>downwards</u> so that the thrust force on the scallop is <u>upwards</u>.

Explanation:

For every action, there is a reaction with the same magnitude but in the opposite way (third law of Newton), so when the scallop ejects water downwards, another force appears that pushes the scallop upwards.

Kitty [74]3 years ago
7 0

Answer

Downward, Upward

Explanation:

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A 12.0-g rock is placed in a slingshot with a spring constant of 200 N/m. The rock is stretched back 0.500 m. After the slingsho
kaheart [24]

The maximum velocity of the rock is 64.55 m/s

Answer: Option B

<u>Explanation:</u>

The possessed energy by the objects while motion called kinetic energy. It is directly proportionate to mass and square of velocity. The stored energy in the system called potential energy and expressed as below,

\text { potential energy }=\frac{1}{2} \times(\text { spring constant }) \times\left(\text { distance from equilibrium) }^{2}\right.

                  U=\frac{1}{2} \times k \times x^{2}

U = spring’s potential energy in certain place

k = the spring constant, in N/m.

x = the spring’s distance is stretched or compressed away from equilibrium

Conservation of energy states energy neither created nor destroyed but change from one form to other. So, using this concept, equating both potential and kinetic energies equation we get,

            \frac{1}{2} \times m \times v^{2}=\frac{1}{2} \times k \times x^{2}

Given:

m = 12 g = 0.012 kg

k = 200 N/m

x = 0.500 m

Substitute these values we get,

         \frac{1}{2} \times 0.012 \times v^{2}=\frac{1}{2} \times 200 \times(0.500)^{2}

         v^{2}=\frac{200 \times 0.25}{0.012}=\frac{50}{0.012}=4166.66

Taking square root, we get,

         v=64.55 \mathrm{m} / \mathrm{s}

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4 years ago
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Answer:

The answer is below!!

Explanation:

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Hope I Helped!!

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6 0
2 years ago
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Answer:

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saveliy_v [14]

" 50 W " means " 50 Watts "  or  " 50 Joules per second ".

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