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sergejj [24]
3 years ago
8

Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is

the electrical force between the two charges?
(k = 9.0 E9 Nm^2/c^2)
A. +1.8 E-2 N and it is repulsive
B. +3.6 E-2 N and it is repulsive
C. +4.5 E-2 N and it is attractive
D. +9.0 E -2 N and it is attractive
Physics
1 answer:
ipn [44]3 years ago
4 0
F = kq1q2/r^2 

<span>q1 is first charge </span>
<span>q2 is second charge </span>
<span>k is 9 E9 </span>
<span>r is distance between them </span>

<span>F = (9E9)(2 E-6)(4 E-6)/2^2 = 0.018 N </span>

<span>A postive answer indicates a repulsive force</span>
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Answer:

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5 0
3 years ago
A set of charged plates 0.00262 m apart has an electric field of 155 N/C between them. What is the potential difference between
mylen [45]

Answer: The potential difference between the plates = 0.4061V

Explanation:

Given that the

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Distance d = 0.00262 m

From the definition of electric field strength, is the ratio of potential difference V to the distance between the plates. That is

E = V/d

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155 = V/0.00262

Cross multiply

V = 155 × 0.00262

V = 0.4061 V

The potential difference between the plates is 0.4061 V

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3 years ago
Things you can do with an environmental engineering major and a broadcasting minor?
Vika [28.1K]

Answer:

With an  Environmental  Engineering  and a broadcasting minor

You can work as an On Air  personality that host  programs that provide your audience with  documentaries about the environments and project carried out by Environmental Engineer

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Explanation:

In order to get a better understanding let define some terms

Environmental Engineer :

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7 0
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A 800-gram grinding wheel 27.0 cm in diameter is in the shape of a uniform solid disk. (We can ignore the small hole at the cent
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Explanation:

d = Diameter of wheel = 27 cm

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m = Mass of wheel = 800 g

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Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-245\times \frac{2\pi}{60}}{50}\\\Rightarrow \alpha=-0.51312\ rad/s^2

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M=\frac{1}{2}mr^2\\\Rightarrow M=\frac{1}{2}\times 0.8\times 0.135^2\\\Rightarrow M=0.00729\ kgm^2

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\tau=I\alpha\\\Rightarrow \tau=0.00729\times -0.51312\\\Rightarrow \tau=-0.0037406448\ Nm

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What is the area
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