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sergejj [24]
3 years ago
8

Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is

the electrical force between the two charges?
(k = 9.0 E9 Nm^2/c^2)
A. +1.8 E-2 N and it is repulsive
B. +3.6 E-2 N and it is repulsive
C. +4.5 E-2 N and it is attractive
D. +9.0 E -2 N and it is attractive
Physics
1 answer:
ipn [44]3 years ago
4 0
F = kq1q2/r^2 

<span>q1 is first charge </span>
<span>q2 is second charge </span>
<span>k is 9 E9 </span>
<span>r is distance between them </span>

<span>F = (9E9)(2 E-6)(4 E-6)/2^2 = 0.018 N </span>

<span>A postive answer indicates a repulsive force</span>
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