Answer:
a) the angular velocity is ω= 82 rad/seg
b) the tangencial acceleration is a = 1.148 m/s²
c) the centripetal acceleration is ac = 941.36 m/s²
Explanation:
for rotational motion
ω= angular velocity
ωo = initial angular velocity
α= angular acceleration
t = time
R= radius
a= tangencial acceleration
ac = centripetal acceleration
a) ω= ωo + α*t = 0 + 8.2 rad/s2 * 10 s = 82 rad/seg
b) a= α*R = 8.2 rad/s2* 14 cm = 114.8 cm/s² = 1.148 m/s²
c) ac= ω²*R = (82 rad/seg)² * 14 cm = 94136 cm/s² = 941.36 m/s²
<span>When the two pucks collide, momentum will still be same but it acts in two different directions.
Momentum formula goes like this M = m x v, m is mass and v is speed. That means velocity is inversely proportional to mass.
So the puck with less weight changes the most, so the 0.156 kg puck changes velocity the most
.</span>
d = distance the bowling ball has fallen = ?
g = acceleration due to gravity acting on the ball by earth = 9.8 m/s²
t = time of fall for the ball = 3.0 s
distance the ball has fallen is given as
d = (0.5) g t²
inserting the above values in the equation above
d = (0.5) (9.8 m/s²) (3.0 s)²
d = (0.5) (9.8 m/s²) (9.0 s²)
d = (4.9 m/s²) (9.0 s²)
d = 44.1 m
hence the distance fallen by the ball comes out to be 44.1 m
The answer for sure is 5 m/s