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Brilliant_brown [7]
3 years ago
13

Which of the following is true about gravity?

Physics
1 answer:
murzikaleks [220]3 years ago
6 0
B, C, and D are your answers.
You might be interested in
Help asap please I will give you 5stars
boyakko [2]

Explanation:

In the parallel combination, the equivalent resistance is given by :

\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+....

4. When three 150 ohms resistors are connected in parallel, the equivalent is given by :

\dfrac{1}{R}=\dfrac{1}{150}+\dfrac{1}{150}+\dfrac{1}{150}\\\\R=50\ \Omega

5. Three resistors of 20 ohms, 40 ohms and 100 ohms are connected in parallel, So,

\dfrac{1}{R}=\dfrac{1}{20}+\dfrac{1}{40}+\dfrac{1}{100}\\\\=11.76\ \Omega

Hence, this is the required solution.

6 0
3 years ago
If the action force is a player kicking a soccer ball, then what is the reaction force?
LiRa [457]
The force acting on his feet.
4 0
3 years ago
A circuit consists of a 12 V battery connected across a single resistor. If the current in the circuit is
finlep [7]

Answer:

4 Ohms

Explanation:

Apply the formula:

Voltage = I (current) . Resistance

You can change it the way you want to use for your purpose.

In this case...

R = V/I

R = 12/3

R = 4 Ohms (Ohm is the unit of measurement of eletrical resistance)

7 0
2 years ago
A distance of 1.0 meter separates the centers of
professor190 [17]
Neither set of choices is correct.

If the distance is tripled, then the forces decrease to

1/9 Fg. and. 1/9 Fe.

Note. When the objects are charged, the gravitational force Fg can almost always be ignored, since Fe is like 10^40 greater when the quantities of mass and charge are similar.
4 0
3 years ago
The accompanying table shows measurements of the Hall voltage and corresponding magnetic field for a probe used to measure magne
aalyn [17]

0.125 mm . is the thickness of the sample.

<h3>What do you mean by hall voltage ?</h3>

The Hall effect is the creation of a voltage difference (the Hall voltage) across an electrical conductor, which is transverse to an applied magnetic field perpendicular to the current and an electric current in the conductor. Edwin Hall made the discovery in 1879.

We need to know the material's current, magnetic field, length, number of charge carriers, and area in order to calculate the Hall voltage. The Hall voltage is computed using the formula: v=IBlneA=(100A)(1.5T)(1.0102m)(5.91028/m3)(1.61019C)(2.0105m2)=7.9106V.

lof4

First we have to plot those point Then we can use some computer program to fit those point linearly to get slope

of that graph a and interception b. We already know, from theory, that Hall's voltage AVH and magnitude of

magnetic field B are connected as

ΔV_{H} =\frac{I}{nqt} B

where I is current trough probe, n is concentration of charge carriers, q = 1.6 • 10¯19 C is charge of charge

carries and t is thickness of the material. We have put the data from the problem on a graph and fitted linearly and

got

a = 100 μ\frac{V}{T}

b = —0.02  μV.

As we can see, our result are in agreement with theoretical assumptions because interception b is almost O, and a

is asked relation between Hall's voltage A VH and magnitude of magnetic field B. Then we can write

ΔVH =100X10^{-6} V/TB

(4) Then we can use result (4) and numbers from the textbook to calculate the thickness of the sample as

a=\frac{I}{nqt} \\t=\frac{I}{anq} \\t=\frac{.200A}{100X10^{-6}X 1.6 X10^{-19}X10^{26}  } \\t=0.125mm

To learn more about the hall voltage , Visit: brainly.com/question/19130911

#SPJ4

8 0
2 years ago
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