Answer:
If the wheelchair is up 7.1 ft. In hight the time of flight should be 0.664 seconds and the distance should be 12.108 ft.
Explanation: I divided the displacement by the time and I used the equation Vx = 20 km/m
3.4 × 10³ N.
<h3>Explanation</h3>
The perpendicular distance between the 400 N force and the fulcrum is .
What's the perpendicular distance between the friction of the nail and the fulcrum?
Refer to the diagram attached. The perpendicular distance between the nail and the fulcrum is .
What's the size of the friction of the nail?
.
Answer:
a) v1 = a1*t1 = 2162 m/s
b) v2 = v1 + a2*(t2-t1) = 2591 m/s
c)
Explanation:
For any movement with constant acceleration:
Vf = vo + a*Δt. Replacing the propper values, with get the answers for parts a) and b):
v1 = a1*t1 = 2162 m/s
v2 = v1 + a2*(t2-t1) = 2591 m/s
Using the formula for displacement we can calculate the total distance asked on part c):
Solving for D and replacing the values for each part of the launch:
D1 = 24863m
D2 = 26141.5m
Finally we add D1 + D2 for the total distance:
D = 51004.5m
Answer:10m/s
Explanation:
Wave speed ,v=for
Where π= wavelength=2m
Period =1/f f=frequency of wave
F=1/period
=1/0.2=5Hz
So speed of waves,v=5×2=10m/s