X is greater than or equal to 5
How many distinct products can be formed using two different integers from the given set: {–6, –5, –4, –3, –2, –1, 0, 1, 2, 3, 4
zhannawk [14.2K]
Number of distinct products that can be formed is 144
<h3>Permutation</h3>
Since we need to multiply two different integers to be selected from the set which contains a total of 12 integers. This is a permutation problem since we require distinct integers.
Now, for the first integer to be selected for the product, since we have 12 integers, it is to be arranged in 1 way. So, the permutation is ¹²P₁ = 12
For the second integer, we also have 12 integers to choose from to be arranged in 1 way. So, the permutation is ¹²P₁ = 12.
<h3>
Number of distinct products</h3>
So, the number of distinct products that can be formed from these two integers are ¹²P₁ × ¹²P₁ = 12 × 12 = 144
So, the number of distinct products that can be formed is 144
Learn more about permutation here:
brainly.com/question/25925367
Answer:
B. 2 is your answer
Step-by-step explanation:
You will use the slope formula to find the slope of the equation.
(3, 7) and (-2, -3) will be used.
7 and -3 are your y's. 3 and -2 are your x's.
(7 - (-3))/(3 - (-2)) = 10/5 = 2
B. 2 is your answer
Answer:
36
Step-by-step explanation:
(7+
)(7- )
this is in the form of a^2-b^2 formula
a^2-d^2=(a-b)(a+b).so write,
(7)^2-( )^2
=49-13
=36
