2 years ago

3 square root of 2 in radical form

Mathematics

1 answer:

Stolb23 [73]2 years ago

3 0

Answer:

Step-by-step explanation:

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Evaluate the expression below:

Olin [163]

Answer:

answer is 16

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2 years ago

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PLEASE HELP ME RN PLEASE

Advocard [28]

Answer:

$\frac{n^{2} - 1 }{2}$

$\sqrt{29}$

Step-by-step explanation:

Area of triangle=1/2×b×h

$\frac{1}{2} \times (n - 1)(n + 1)$

$\frac{( {n}^{2} + n - n - 1) }{2 }$

$\frac{ {n}^{2} - 1 }{2}$

2. Area of triangle=14

$\frac{ {n}^{2} - 1 }{2} = 14$

${n}^{2} - 1 = 28$

${n}^{2} = 29$

$n = \sqrt{29}$

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3 0

2 years ago

What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve. mc017-1.jpg and x = 1 mc017-2.jpg and x = –1 mc

Wittaler [7]

We are given equation : $x^6+6x^3+5=0$

$Use\:the\:rational\:root\:theorem$

$\mathrm{Therefore,\:we\:need\:to\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:5}{1}$

$-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1$

$\mathrm{Compute\:}\frac{x^6+6x^3+5}{x+1}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }x^5-x^4+x^3+5x^2-5x+5$

Therefore, final factored form it

$x^6\:+\:6x^3\:+\:5=\left(x+1\right)\left(x^5-x^4+x^3+5x^2-5x+5\right)$

We can't factor it more.

Therefore,

x+1=0.

x=-1.

Therefore, the real solution of the equation would be -1.

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3 years ago

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3) An archer applies an average force of 200 N to draw the bow string back 1.3 m.

Schach [20]

Step-by-step explanation:

W=N•D

W=(200)(1.3)

W= 260

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2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B64%7D%20%7D%20" id="TexFormula1" title=" \sqrt{64} } " alt=" \sqrt{64} } " align=

aleksklad [387]

Answer:

8 is your answer ^_^

Step-by-step explanation:

8 0

2 years ago