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jek_recluse [69]
3 years ago
15

Which is less (-25)+12 or 40+(-63) ​

Mathematics
2 answers:
Tamiku [17]3 years ago
5 0
(-25)+12= 13
40+(-63)= -23
The second one is less
SIZIF [17.4K]3 years ago
3 0

Answer:

answer is 40+(-63)

Step-by-step explanation:

(-25)+12=-13

40+(-63)=-23

so -13>-23

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Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0
natita [175]

Answer:

\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

Step-by-step explanation:

Given differential equation,

(x^2 + y^2) dx + (x^2 - xy) dy = 0

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Let y = vx

Differentiating with respect to x,

\frac{dy}{dx}=v+x\frac{dv}{dx}

From equation (1),

v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}

v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}

v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}

v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}

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x\frac{dv}{dx}=\frac{v+1}{v-1}

\frac{v-1}{v+1}dv=\frac{1}{x}dx

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\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx

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\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

5 0
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